All categories

3 years ago

13 = -7 + 9x - 5x X =

Mathematics

1 answer:

brilliants [131]3 years ago

3 0

Answer:

x = 5

Step-by-step explanation:

Given

13 = - 7 + 9x - 5x , that is

13 = - 7 + 4x ( add 7 to both sides )

20 = 4x ( divide both sides by 4 )

5 = x

You might be interested in

Which difference is about 10?

Helga [31]

Option B is the answer.

70.9 - 58.7

4 0

3 years ago

(-2/3) to 2nd Power - 3/4 (2 1/3) Will give out 50+25 pts and Brainliest Answer

trasher [3.6K]

I think the answer is -47/36

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to (s+7) + 8 by the Associative Property of Addition? *

Maurinko [17]

An equivalent expression would be s+15

You simplify the expression.

So yea the answer is s+15

7 0

2 years ago

Read 2 more answers

The parabola opens upward has x = 2 as an axis of symmetry and contains the non -vertex points (1, 9) and (4, 27) write the equa

Sedaia [141]

Answer:

Step-by-step explanation:

f(x) = a(x - h)² + k - vertex form of the equation of the parabola with vertex (h, k)

"the parabola opens upward" means: a>0

"the parabola has x = 2 as an axis of symmetry" means: h = 2

so f(x) = a(x - 2)² + k

"the parabola contains the point (1, 9)" means:

9 = a(1 - 2)² + k

9 = a(-1)² + k

9 = a + k

k = 9 - a

"the parabola contains the point (4, 27)" means:

27 = a(4 - 2)² + k

so:

27 = a(2)² + 9 - a

27 = 4a + 9 - a

3a = 18

a = 6

and k = 9 - 6 = 3

Therefore the vertex form for this parabola is:

f(x) = 6(x - 2)² + 3

4 0

3 years ago

The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin

quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

So, According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of The inscribed circle

So, the center of The inscribed circle is the point S

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

So, According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of The circumscribed circle

So, the center of The circumscribed circle is the point P

5 0

3 years ago