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NemiM [27]
3 years ago
5

What is the solution of the equation 4x + 3y = 12 7x + 5y = 26

Mathematics
1 answer:
malfutka [58]3 years ago
4 0
The solution would be B) (18,-20)
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Angles α and β are angles in standard position such that: α terminates in Quadrant I and sinα = 3/5 β terminates in Quadrant III
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Answer:

-16/65

Step-by-step explanation:

Given sinα = 3/5 in quadrant 1;

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adj^2 = 5^2 = 3^2

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Since all the trig identity are positive in Quadrant 1, hence;

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Similarly, if tanβ = 5/12 in Quadrant III,

According to trig identity

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Since only tan is positive in Quadrant III, then;

sinβ = -5/13

cosβ = -12/13

Get the required expression;

sin(α - β) = sinαcosβ - cosαsinβ

Substitute the given values

sin(α - β) = 3/5(-12/13) - 4/5(-5/13)

sin(α - β)= -36/65 + 20/65

sin(α - β) = -16/65

Hence the value of sin(α - β) is -16/65

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