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Serga [27]
2 years ago
11

PlEaSe HeLp GiViNg BrAiNlIeSt​

Mathematics
2 answers:
Romashka-Z-Leto [24]2 years ago
8 0

2. The total number of ski trails is 12. That's how many numbers there are in the box.

3. The difference in length between the longest ski trail and the shortest ski trail is the biggest number minus the smallest number in the box. 3 1/8 minus 1 3/8 is 1 and 3/4. So the answer is 1.75 or 1 3/4, whichever one works.

4. There are 3 trails that are 2 7/8 miles long. so You do 2 7/8 times three or 2 7/8 plus 2 7/8 plus 2 7/8. That equals 8 19/40 which is the answer. Ti add them together first turn them into mixed numbers. 2 7/8 is the same as 23/8. 8x3=24.  23x3=69. 69/24 is the same is 8 19/40 through further simplification.

5. 3 1/8 plus 1 3/8 is 4 1/2 or 4.5

6. The shortest ski trail is 1 3/8.   1 3/8 times 3 is 4.125. 4 is greater than 3 which means Sam is automatically right.

AlladinOne [14]2 years ago
7 0

Answer:

1. See attached for dot plot

2. 12

3. longest ski trail = 3\frac14

  shortest ski trail = 1\frac38

  ⇒ difference = 3\frac14-1\frac38=1\frac78 miles

4. There are 3 trail that are 2\frac78 miles long.

   ⇒ total length = 3 \times 2\frac78=8\frac58 miles

5. Sum of shortest trail and longest trail = 3\frac14+1\frac38=4\frac58 miles

6. 3 times the shortest trail = 3 \times 1\frac38=4\frac18 miles

   longest trail = 3\frac14 miles

   Therefore, Eli is correct as 3\frac14

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3 years ago
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Answer:

(1,11)

Step-by-step explanation:

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y=8x+3

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3 years ago
Three points are colinear.<br> always<br> sometimes <br> never
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6 0
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I’m need this worked out step by step by tonight
Pie

9514 1404 393

Answer:

  -3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

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Multiply all parts by 2.

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_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

  |(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

__

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

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If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

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