6.8,6.827,6.86,6.9
1.2,1.203,12.03, 12.301,12.31
First, we need to know the smallest two digit prime number. It can't start with one, since one is not prime, so it must start with two (or be in the twenties.) 20 is divisible by 2, 4, 5, and 10, 21 is divisible by 7 and 3, 22 is divisible by 2 and 11, so the smallest prime number is 23.
Now we need the largest two-digit prime number. It cannot start with nine or eight, since both are composite, so it must start with seven (be in the seventies.) 79 is the largest integer in the seventies and also happens to be prime, so there's our largest two digit prime number.
now we just need to add them for the sum:
23+79=102
hope I helped, and let me know if you have any questions :D
We try to represent the data in segments from 0 to 20.
<span>The length of the line segment along the number line from 0 to 5 is 5 - 0 = 5 units. The length of the line segment along the number line from 20 to 5 is 20 - 5 = 15 units. If you were to randomly throw a dart on this number line, then the probability of landing in the shaded region is 15/20 = 3/4 or 75%</span>
<span>Length of outer track = sum of length of 10 pieces = circumference of the outer circle
if R is the Radius of outer circle then...
Circumference of the outer track = 2pi*R
Similarly the circumference of the inner track (with radius r) = 2pi*r
length of each outer piece is 3.4 inch more than length of inner piece
So total outer length is 10*3.4 =34 inches more than the inner length.
=> Outer Circumference - Inner Circumference = 34 inches
=> 2pi*R - 2pi*r = 34
=> 2pi(R -r) = 34
=> R-r = 34/2pi = 5.41 inches
=> R-r = Width of the track = 5.41 inches</span>
Answer:
The probability of drawing the first pink ball is 
.
Because you drew that first pink ball, there are two pink balls left and the total number of balls left is nine.
Hence, the probability of drawing another pink ball after drawing the first pink ball would be:
