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3 years ago

If ab = 8 and a^2 + b^2 = 16, then what is the value of (a+b)^2? 25 POINTS

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

8 0

Answer:

Step-by-step explanation:

(a+b)²=a²+2ab+b²=(a²+b²)+2ab=16+2*8=32

erik [133]3 years ago

6 0

Answer:

Step-by-step explanation:

Note that

(a + b)² = a² + 2ab + b²

= a² + b² + 2ab ← substitute given values for a² + b² and ab

= 16 + (2 × 8)

= 16 + 16

= 32

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