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AlladinOne [14]
3 years ago
13

I need help on this???

Mathematics
2 answers:
Aliun [14]3 years ago
4 0
Use the geometric mean for right triangles here.  Like this \frac{9}{y}= \frac{y}{7}.  Cross multiply to get y^{2}=63, and y= \sqrt{63}.  That simplifies down to y= \sqrt{9*7}.  Pull out the 9 as a perfect square of 3 and you're left with y=3 \sqrt{7}, first choice above.
Hitman42 [59]3 years ago
3 0
Another way to do this is to apply pythagoras 3 times, since there are 3 right triangles. Assuming the sides not named here are a and b, you get:

a^2 + b^2 = 16^2
9^2 + y^2 = a^2
y^2 + 7^2 = b^2

You can solve these to y=3√7
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Consider the geometric sequence below.
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Answer:

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Step-by-step explanation:

f(1) means the firs term in a sequence.

In the function f(n), represented by 8, 4, 2, 1, .., the first term is 8.

f(1) = 8

To find the common ratio, divide any term by the term before it.

We can use any two of the given terms in the sequence EXCEPT for 8 because it is the first term and does not have a term before it.

I choose to divide the second term by the first term:

4/8 = 1/2 = 0.5

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a round plane figure whose boundary (the circumference) consists of points equidistant from a fixed point (the center).

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The skittles jar has a radius of 3.5 cm and a height of 11.5 cm. using the two given boxes for reference what would be a good es
Bond [772]

C) 1059 skittles

Step-by-step explanation:

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Volume of 258 skittles = 12 × 3 × 3 = 108 cm³

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We found that the volume of  1 skittle is equal to 0.42 cm³. Now we calculate the volume of the skittles jar:

volume of cylinder = π × radius² × height

volume of skittles jar = 3.14  × 3.5² × 11.5 = 442 cm³

Now we can calculate the number of skittles in the jar:

number of skittles in the jar = volume of the jar / skittle volume

number of skittles in the jar = 442 / 0.42 = 1052 which is close the C) 1059

Learn more about:

volume of cylinder

brainly.com/question/12748872

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Please help me with problem 1 of Properties of Multiplication with Whole Numbers
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This is the associative property, since any numbers can <em>associate </em>with each other, via the parentheses.

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