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3 years ago

10

Bill spent 50% of his savings on school supplies, then he spent 50% of what was left on lunch. If he had $6 left after lunch, ho

w much did he have in savings at the beginning?

2 answers:

Lera25 [3.4K]3 years ago

6 0

If he spent half his savings on supplies and the other half on lunch he shouldn't have money left over. It's a trick question.

Vaselesa [24]3 years ago

4 0

He wouldn’t have money left

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A jellyfish travels 3/5 mile in 1/6 hour and a walrus travels 5/6 mile in 3/10 hour.

emmasim [6.3K]

Answer:

The jellyfish travels faster than the walrus

Step-by-step explanation:

Given data

A jellyfish travels 3/5 mile in 1/6 hour

Distance= 3/5 mile

time= 1/6 hour

speed= distance/time

speed= 3/5/1/6

speed= 3/5*6/1

speed= 18 mile per hour

a walrus travels 5/6 mile in 3/10 hour.

Distance= 5/6 mile

time= 3/10 hour.

speed= distance/time

speed= 5/6/3/10

speed= 5/6*10/3

speed= 50/18 mile per hour

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Érica has saved $24, which is 40% of the total amount she needs to buy a new video game. How much does she need total to buy the

d1i1m1o1n [39]

Do 40/100=24/x and cross multiply

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3 years ago

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s344n2d4d5 [400]

Answer:eht sistep 2 and step 4 is the correct answer

Step-by-step explanation:

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2 years ago

Help with question 7, 8 and 9

ehidna [41]

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3 years ago

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If A^2=A, which matrix is matrix A

Ronch [10]

Consider all options:

A.

$\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] \cdot \left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] =\left[\begin{array}{cc}5\cdot 5+5\cdot (-4)&5\cdot 5+5\cdot (-4)\\-4\cdot 5+(-4)\cdot (-4)&-4\cdot 5+(-4)\cdot (-4)\end{array}\right]=$

$=\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right].$

This option is true.

B.

$\left[\begin{array}{cc}6&5\\5&6\end{array}\right] \cdot \left[\begin{array}{cc}6&5\\5&6\end{array}\right] =\left[\begin{array}{cc}6\cdot 6+5\cdot 5&6\cdot 5+5\cdot 6\\5\cdot 6+6\cdot 5&5\cdot 5+6\cdot 6\end{array}\right]=$

$=\left[\begin{array}{cc}61&60\\60&61\end{array}\right].$

This option is false.

C.

$\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+(-0.5)\cdot (-0.5)&0.5\cdot (-0.5)+(-0.5)\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot (-0.5)+0.5\cdot 0.5\end{array}\right]=$

$=\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right].$

This option is true.

D.

$\left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+0.5\cdot (-0.5)&0.5\cdot 0.5+0.5\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot 0.5+0.5\cdot 0.5\end{array}\right]=$

$=\left[\begin{array}{cc}0&0.5\\-0.5&0\end{array}\right].$

This option is false.

E.

$\left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] \cdot \left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] =\left[\begin{array}{cc}-6\cdot (-6)+(-6)\cdot 5&-6\cdot (-6)+(-6)\cdot 5\\5\cdot (-6)+5\cdot 5&5\cdot (-6)+5\cdot 5\end{array}\right]=$

$=\left[\begin{array}{cc}6&6\\-5&-5\end{array}\right].$

This option is false.

Answer: correct options are A and C.

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3 years ago

Read 2 more answers