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3 years ago

Name the different forms of linear equations you learned. If (1, 2) and

Mathematics

2 answers:

Deffense [45]3 years ago

8 0

<h2>Answer:</h2>

The solution to this exercise has been attached below. The problem has been solved in this way:

________________

<h2>1. Different forms of linear equations. Point slope-intercept equation of the line that passes through two points.</h2><h2>2. Inverse Function. </h2><h2>3. Average Rate of Change.</h2><h2>4. Comparison of linear equations and inequalities</h2><h2>5. Real-life problems</h2><h2>6. Imaginary Number</h2><h2>7. Radicals</h2><h2>8. Rational exponent and radical form</h2><h2>9. Radical expressions</h2><h2>10. Quadratic equation</h2><h2>11. Trinomial</h2><h2>12. Factoring expressions</h2><h2>13. Quadratic and linear graph</h2><h2>14. A problem of height</h2>

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mihalych1998 [28]3 years ago

4 0

Answer:

Everything he said was correct!

Step-by-step explanation:

I hope this helps!

- sincerelynini

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Tia is investing $2500 that she would like to grow to $6000 in 10 years. At what annual interest rate, compounded quarterly, mus

Ghella [55]

$\bf \qquad \textit{Compound Interest Earned Amount}\\
A=P\left(1+\frac{r}{n}\right)^{nt}

\\ \quad \\

\begin{cases}
A=\textit{current amount}\to &6,000\\
P=\textit{original amount deposited}\to &\$2,500\\
r=rate\to r\%\to \frac{r}{100}\to &0.0r\\
n=\textit{times it compounds per year, quarterly}\to &4\\
t=years\to &10
\end{cases}
\\ \quad \\
meaning
\\ \quad \\

6,000=2,500\left(1+\frac{r}{4}\right)^{4\cdot 10}$

solve for "r"

notice, the "r" value, goes in the equation as a decimal, so 5% is really 5/100 or 0.05 25% is 0.25 and so on

so... the "r" that you'll get, will be a decimal value, multiply that by 100, and you'll get the percentage notation of it

$\bf 6,000=2,500\left(1+\frac{r}{4}\right)^{4\cdot 10}\implies\cfrac{6000}{2500}=\left(1+\frac{r}{4}\right)^{40}
\\ \quad \\
\cfrac{12}{5}=\left(1+\frac{r}{4}\right)^{40}\impliedby \textit{now, taking root }\sqrt[40]{\qquad }
\\ \quad \\
\sqrt[40]{\cfrac{12}{5}}=\sqrt[40]{\left(1+\frac{r}{4}\right)^{40}}\implies \sqrt[40]{\cfrac{12}{5}}=1+\cfrac{r}{4}
\\ \quad \\
\sqrt[40]{\cfrac{12}{5}}-1=\cfrac{r}{4}\implies 4\left( \sqrt[40]{\cfrac{12}{5}}-1 \right)=r \\ \quad \\
$
$\bf 0.0885119586095070592=r\implies 0.0885\cdot 100\implies 8.85\%=r$

5 0

3 years ago

Simplify to create an equivalent expression<br><br> -y minus -3(-3y+5)

Gemiola [76]

Answer:

8y-15

Step-by-step explanation:

-y-3(-3y+5)

-y+9y-15

8y-15

5 0

3 years ago

9. What is the value of x?<br> Drawing not to scale<br> 61<br> 37<br> 85<br> 122

Zepler [3.9K]

The answer for the question is 61

5 0

2 years ago

Read 2 more answers

2- 1/2n=3n+16<br><br> I need you to solve the whole equation step by step

Alex Ar [27]

Answer:

n = -4

Step-by-step explanation:

2 - 1/2 n = 3n + 16

Combine the constants by subtracting 2 from both sides.

-1/2n = 3n + 14

Combine the variable by subtracting 3n from both sides.

-7/2n = 14

Multiply both sides by 2 to simplify the fraction.

-7n = 28

Isolate n by dividing by -7 on both sides.

n = -4

Check.

2 - 1/2(-4) = 3(-4) + 16

2 + 2 = -12 + 16

4 = 4

Your answer is correct.

3 0

2 years ago

Read 2 more answers

The cost of going to a drive-in movie theater is $5. 50 per person plus $2. 75 per car. Use the dropdown menu to create an algeb

Pie

The algebraic equation which shows that the number of <em>x </em>people can go to the drive-in with one car for $19. 25 is,

$5.50x+2.75=19.25$

<h3>How to write algebraic equation?</h3>

Algebraic equation are the expression which consist the variables, coefficients of variables and constants.

The algebraic expression are used represent the general problem in the mathematical way to solve them.

Steps to write down the simple algebraic equation-

Identify all the factors of the expression.
Assume a variable for the changing values.
Put a coefficient for the variable, if there is any rate of change of variable.
Use constant numbers for the fixed values.

The cost of going to a drive-in movie theater is $5.50 per person plus $2.75 per car. It has to create an algebraic equation that shows how many people can go to the drive-in with one car for $19. 25.

Suppose the total number of people in the car for drive-in movie theater is <em>x</em>. Thus, the cost of the<em> </em><em>x</em> person to watch the movie is,

$C=5.50x$

As the cost of one car is $2.75. Thus, the total cost of watching a movie by x person will be,

$C=5.50x+2.75$

Now, the total cost, drive-in with one car for $19. 25. This cost must be equal to the above expression for total cost. Therefore,

$C=5.50x+2.75=19.25$

Hence, the algebraic equation which shows that the number of <em>x </em>people can go to the drive-in with one car for $19. 25 is,

$5.50x+2.75=19.25$

Learn more about the algebraic expression here;

brainly.com/question/2164351

7 0

2 years ago