5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles

Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30

7 0

3 years ago

8x+3y=18

Minchanka [31]

Step-by-step explanation:

8x+3y=18

subject y according y=mx+c

y=8/3x-6

(-9,-13)

substitute -9 to y=8/3x-6

-13=8/3×(-9)+c

11=c

y=8/3x+11

3 0

3 years ago

ron wants to build a ramp with a length of 14 ft and an angle of elevation of 26° the height of the ramp is about 6.1 ft. what i

Bezzdna [24]

Answer:

12.58 feet.

Step-by-step explanation:

Ron wants to build a 14 ft. ramp with an angle of the rise of 26° and the height of the ramp is about 6.1 ft.

We have to find out the length of the base of the ramp.

Now, the ramp forms a right triangle with the base and the height and here, the hypotenuse of the triangle is the ramp itself i.e. 14 ft.

If the base length is x feet, then we can write using the trigonometry

$\cos 26^{\circ} = \frac{\textrm{Base}}{\textrm {Hypotenuse}} = \frac{x}{14}$

⇒ x = 14 cos 26° = 12.58 feet. (Answer)

4 0

3 years ago