Answer:
40824
Step-by-step explanation:
hi im here
Given:
The function is:

To find:
The initial value of the function.
Solution:
We have,

The value of the function at x=0 is called the initial value of the function.
For x=0, we get


Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.


Therefore, the initial value of the function is 350.
me so sorry come back laterAnswer:
Step-by-step explanation:me so sorry come back later
Answer:
5^(3)i^(9)= five cubes times i to the power of 9=125i
Step-by-step explanation:
Raise 5 to the power of 3
rewrite i9 as (i^4)2^i
so, you get 125((i^4)^2i)
i^4=1
125(1^2i)
125i
Answer
Step-by-step explanation: