1..... 8(x+6)=-64
8x+48 =-64
8x =-64-48
8x=-112
X=-112/8
x=-14....
2.....3(4-2y)=-15
12-6y=-15
-6y=-15-12
-6y = - 27
y=27/6
y=4½....
3.....8w-3w+6=41
5w=41-6
5w=35
W=35/5
w=7....
4.....9x+3+x=-77
10x=-77-3
10x=-80
x=-8...
5.....10(-x-2)=120
-10x-20=120
-10x=120+20
-10x=140
x=140/-10
x=-14...
You shouldn't have a problem with the rest now....
Answer:
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Step-by-step explanation:
The problem states that:
Of the ticks that carry at least one of these diseases in fact carry both of them.
So, if a tick carries one of these diseases, there is a 100% probability that is carries another.
What is the probability that the selected tick is also a carrier of Lyme disease?
There is a 100% probability that the selected tick is also a carrier of Lyme disease.
Answer:
a: $60.45
b: 20
Step-by-step explanation:
I did this on a test!
I believe the answer is
2 and 1/5
