Another way is to note that there are <span><span>(<span>104</span>)</span><span>(<span>104</span>)</span></span> (“10 choose 4”) ways to select 4 balls from a collection of 10. If 4 of those 10 balls are “special” in some way (in this case, “special” = “red”), then the number of ways to choose 4 special balls is <span><span>(<span>44</span>)</span><span>(<span>44</span>)</span></span>. (The factor of <span><span>(<span>60</span>)</span><span>(<span>60</span>)</span></span> is included to convey that, after choosing 4 special balls, we choose none of the 6 non-special balls.) This line of reasoning gives the second expression.
I believe that it is B. Hope this helps!
Answer:
the law of bodmas multiplication first so
40+(40*0)+1
40+1
41
Yes your correct but thats not a question
<span>The cosine of an angle is the quotient of the side that angle lay on and the hypotenuse.</span>
x-hypotenuse
cos45=19/x
0.707=19/x, x=19/0.707, x=26.9
Hypotenuse is <span>approximately 27.</span>
