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kompoz [17]
3 years ago
8

Oleander (Nerium oleander) is a common but poisonous ornamental shrub. All parts of the plant contain chemicals that inhibit the

Na+/K+ pump. How would this affect sodium-glucose symporters (secondary active transport) of a given cell?
Biology
1 answer:
Rudiy273 years ago
7 0

Answer:

Glucose levels within the cell would decrease

Explanation:

Sodium glucose simulators are proteins that participate in secondary active transport within epithelial cells. This type of protein can be located in the cell membrane and has the function of transporting glucose and sodium into cells simultaneously. These proteins are directly dependent on Na+/K+ pumps, as they use the free energy released by them to efficiently transport sodium and glucose. For this reason, we can conclude that if a plant's chemicals inhibit the Na+/K+ pump, glucose and sodium concentrations will decrease because the proteins responsible for their transport into the cell will be weakened by a lack of energy.

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The lock-and-key mechanism refers to a) the complementary shapes of an enzyme and a substrate. b) the attractive forces between
podryga [215]

Answer:

A. The complementary shapes of an enzyme and a substrate

Explanation:

The Lock-and-Key model was made to show how an enzyme's active zone fits a substrate and how they bond together. It correlates just like a lock and a key; you have to have the correct-shaped key in order to open a lock. Same process of thought with the enzymes; you must have the same shape for both in order to bind together,

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An ecosystem engineer can cause a cascade of effects including abiotic and biotic changes.
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Answer:

O True

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3 years ago
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8 0
2 years ago
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Which map symbol is associated with extremely low air pressure? <br>​
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3 years ago
What would be the most likely effect on the transcription of the trp structural genes for the mutation scenarios provided? mutat
blagie [28]

Answer:

I've responded to each scenario individually, please see below:

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No transcription occurs

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Transcription when alanine is low

3. mutation that creates a stop codon in region 1 of mRNA 5' UTR

Transcription occurs, a truncated protein will be made during translation

4. deletions in region 2 of the mRNA 5' UTR

Transcription occurs, region 1 and 2 might get paired together

5. deletions in region 3 of the mRNA 5' UTR

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6. deletions in region 4 of the mRNA 5' UTR

Transcription occurs, region 3 and 4 could combine to form a hairpin loop structure

7. deletion of the string of adenine after region 4 of the mRNA 5' UTR

Transcription occurs, however, it will not be as stable a molecule because of losing its polyA tail

Hope that answers the question, have a great day!

6 0
3 years ago
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