Answer:
Step-by-step explanation:
You want to set up a system. We are given some points fo we can set up inputs and outputs. F(0) = 5, given by point (0,5). and F(3)=135, given by point (3,135). The exponential function general equation is F(x)= a(b)^x. plug in out functions into the general equation to get a(b)^0=5 and a(b)^3=135. Then you simplify and solve for a. In the equation a*b^0=5, anything to the power of 0 is 1. so a*1=5. Therefore a=5. we plug in the a to the second equation to find b. 5*b^3=135. b^3=27. b=3 from simplifying. Therefore, the equation should be 5(3)^x. THATS IT!
1. since the equations equal each other
2x+19=x+7
-x -x
x+19=7
-19 -19
x= -12
sub into y= x+7
y= -12+7
y= -5
2. x+2y=-7
<span>x+y+23=0
i don't know what the second equation is equal to, i'll assume 0
2y=x-7
y=1/2x-7/2
sub this into x+y+23=0
x+1/2x-7/2+23=0
3/2x+39/2=0
-39/2 -39/2
3/2x= -39/2
x=-39/2 / 3/2
x= -13
sub into y=1/2x-7/2
y=1/2(-13)-7/2
y= -10
3. </span>x+5y=2
<span>x=-4y+5
</span>sub x=-4y+5 into x+5y=2
-4y+5+5y=2
y+5=2
-5 -5
y= -3
sub y =-3 into x =-4y+5
x=-4(-3)+5
x= 17
4. 3x+y=9
<span>y=-5x+9
</span>sub -5x+9 into 3x+y=9
3x+(-5x+9)=9
3x-5x+9=9
-2x+9=9
-9 -9
-2x=0
x=0
sub into y=-5x+9
y=-5(0)+9
y=9
Answer:
Step-by-step explanation:
hello :
x3^-8=0 means : x3^=8
but : 8 = 2^3
so : x3^= 2^3
x=2
I'm assuming you mean (a-b)^2 : (a+b)^2
a^2 + b^2 cancel out leaving
-2ab versus +2ab
Therefore (a+b)^2 is +4ab greater.
