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mars1129 [50]
3 years ago
11

Answers for these two questions

Mathematics
1 answer:
marin [14]3 years ago
6 0

Answer:

1. a) the square root of 20

2. d) the square root of 52

Explanation:

we can use the formula of pythagoras' theorem, which is a² + b² = c² (with c being the hypotenuse of a right-angled triangle while a and b are its other two sides), to solve these questions.

for the first question, we can place the given values into the equation to get 4² + b² = 6², with b being the unknown here. b is thus equivalent to 6² - 4², or <u>√20</u>.

for the second question, we can get 4² + 6² = c², which is the unknown value in this question. it would be <u>√52</u>.

i hope this helps! :D

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We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.  

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\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}  

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Now let us find distance between vertex B and vertex C.

\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}

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Now let us find distance between vertex C and vertex D.

\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}

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Now let us find distance between vertex D and vertex A.

\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}  

\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}    

\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}

\text{Distance between vertex D and vertex A}=\sqrt{25}=5

Now let us add all these distances to find the total distance walked by Jared.  

\text{Total distance walked by Jared}=8+5+8+5

\text{Total distance walked by Jared}=26  

Since we have been given that one unit on the grid equals 1 yard,   therefore, Jared walked a distance equal to 26 yards.  

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