The sum of the digits of a three-digit number is 16 .the tens digit is two more than the units digit and the unit digit is tripl
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now, notice the template above... now let's see your function
so.. what do you think was the shift then?
We have the equation:
We know two points and we will use them to calculate the parameters a and b.
The point (0,3) will let us know a, as b^0=1.
Now, we use the point (2, 108/25) to calcualte b:
Then, we can write the equation as: