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3 years ago

Two fractions have a common which of the following could be the two fractions

Mathematics

1 answer:

devlian [24]3 years ago

3 0

3/6 and 1/2 I hope this helps sorry if it doesn't

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Rectangular classroom seats 72 students. If the seats were rearragned with 3 more seats rows in each row, the classroom would ha

Gre4nikov [31]

Let the original number of seats in a row be x;
Let the number rows be y;

( x + 3) * (y - 2 )= 72 and x * y = 72 => 72 + 3 * y - 2 * x = 72 => 3 * y = 2 * x;
=> x is divisible by 3;

1. x = 3 => y = 72 / 3 => y = 24;
2. x = 6 => y = 72 / 6 => y = 12;
3. x = 9 => y = 72 / 9 => y = 8;
4. x = 12 => y = 72 / 12 =. y = 6;
5. x = 24 =. y = 72 / 24 => y = 3;
6. x = 36 => y = 72 / 36 => y = 2;
7. x = 72 => y = 72 / 72 => y = 1;

My analysis tell me that the right answer is 9 seats in a row and 8 rows;
The original number in each row is 9.

6 0

3 years ago

An SRS of 450 450 high school seniors gained an average of ¯ x = 20 x¯=20 points in their second attempt at the SAT Mathematics

maria [59]

Answer: (15.47, 24.53)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :_

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where n= sample size.

$\sigma$ = standard deviation.

$\overline{x}$ = sample mean.

z*= Critical value.

Given : n= 450

$\overline{x}=20$

$\sigma=49$

Critical value for 95% confidence = z*=1.96 [From z-value table]

Then, the 95% confidence interval will be :-

$20\pm (1.96)\dfrac{49}{\sqrt{450}}$

$\approx 20\pm (1.96)(2.31)$

$\approx 20\pm 4.53$

$=(20-4.53,\ 20+4.53)=(15.47,\ 24.53)$

Hence, the 95% confidence interval for the mean change in score μ μ in the population of all high school seniors. : (15.47, 24.53)

3 0

3 years ago

Find all values of x that make the equation true. 3/x-4 = x-5/x

Svetllana [295]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Simplify (1-√3)(⅓+√3) leaving your answer in the form p+q√3

Mars2501 [29]

Answer:

$\frac{-8 +2\sqrt{3} }{3}$

Step-by-step explanation:

When working with surds we need to take note of the roots present there.

To expand this equation we can do it the following way noting that √3 X √3 = 3

Expanding (1-√3)(⅓+√3)

1 X 1/3 = 1/3

1 X √3 = √3

-√3 X 1/3 =-√3/3

√3 X √3 = 3

hence, expanding the equation, we have

1/3 + √3 -√3/3 + 3

We can simply group the like terms and add them up.

[1/3 +3] +[√3-√3/3]

10/3 + $\frac{2\sqrt{3} }{3}$

= $\frac{-8 +2\sqrt{3} }{3}$

8 0

3 years ago

The perimeter of a rectangular pool is 306m. If the length of the pool is 87m, what is its width?

s344n2d4d5 [400]

Answer: the width is 66

Step-by-step explanation: see if 87m is the width then you add it twice it equals 174 then you subtract it from 306m which equals 132 but since theres two sides you divide it to get 66 Hope this help happy Easter!! c:

4 0

3 years ago