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VladimirAG [237]

3 years ago

8

Find direction numbers for the line of intersection of the planes x + y + z = 1 and x + z = 0. (enter your answers as a comma-se

parated list.)

1 answer:

Soloha48 [4]3 years ago

7 0

<1, 1, 1> × <1, 0, 1> = <1, 0, -1>

The cross product of the normals of the planes gives the direction vector of their line of intersection.

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Help me answer this question please

Stella [2.4K]

ANSWER

${f}^{ - 1} =\pm \sqrt{x + 1}$

EXPLANATION

The given function is

$f(x) = {x}^{2} - 1$

Let

$y = {x}^{2} - 1$

Interchange x and y to get:

$x= {y}^{2} - 1$

Solve for y,

$x + 1 = {y}^{2}$

Take square root of both sides to get,

$\pm \sqrt{x + 1} = y$

This is the same as:

$y = \pm \sqrt{x + 1}$

Therefore the inverse is

${f}^{ - 1} =\pm \sqrt{x + 1}$

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