Answer:
sry I just wanted the points I'm in middle school so I don't know this stuff either
Answer:
4x-y+1=0
Step-by-step explanation:
here,given equation of a line id
4x-y-2=0.. eqn(i)
equation of any line parallel to line (i) is
4x-y+k=0...eqn(ii)
since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]
4*1-5+k=0
or, 4-5+k=0
or,-1+k=0
•°•k=1
substituting the value of k=1 in eqn(ii),
4x-y+1=0 is the required equation of the line.
Answer:
-46
Step-by-step explanation:
4 - 2(a^2 – b^2)^2 =
= 4 - 2(3^2 – 2^2)^2
= 4 - 2(9 - 4)^2
= 4 - 2(5)^2
= 4 - 2(25)
= 4 - 50
= -46
Answer:
I think the answer is 1
Step-by-step explanation:
-49÷7=-7
-7÷-7=1
I will get you started.
x^2+4x-4 = 8
x^2 + 4x - 4 - 8 = 0
x^2 + 4x - 12 = 0
You must now use the quadratic formula.
In the formula, a = 1, b = 4, and c = -12.
Take it from here.