Degree days are the difference between the daily temperature mean, (high temperature plus low temperature divided by two) and 65°F. 65°F because we assume that at this temperature we do not need cooling or heating.
In our case the daily mean temperature is 83°F and X is the number of cooling-degree days.
X=83-65
X=18
<span>f(-10)=12, x = -10, y = 12
f(16)=-1, x = 16, y = -1.
so, we have two points, let's check with that,
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![\bf \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)} y-12=-\cfrac{1}{2}[x-(-10)] \\\\\\ y-12=-\cfrac{1}{2}(x+10)\implies y-12=-\cfrac{1}{2}x-5\implies y=-\cfrac{1}{2}x+7](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%20y-12%3D-%5Ccfrac%7B1%7D%7B2%7D%5Bx-%28-10%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay-12%3D-%5Ccfrac%7B1%7D%7B2%7D%28x%2B10%29%5Cimplies%20y-12%3D-%5Ccfrac%7B1%7D%7B2%7Dx-5%5Cimplies%20y%3D-%5Ccfrac%7B1%7D%7B2%7Dx%2B7)
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Answer:
33m^33+2f^22+6f+5
Step-by-step explanation:
this is the answer for if you are supposed to be simplifying :)
Given parameters:
Length of the gift box = 8 inches
Width of the box = 3 inches
Height of the box = 4 inches
Unknown :
Length of its longest diagonal = ?
Solution:
This is a rectangular box.
To find the diagonal of such box, let us use the formula below;
Diagonal = 
l is the length
w is the width
h is the height
Input the parameters and solve;
Diagonal =
= 9.4inches
The diagonal of the box is 9.4inches
Answer:
6 units
Step-by-step explanation:
use imagination to separate the triangle from the square.
2*2 is 4 which is the volume of the square part
2*2/2 is the volume of the triangle which divides out to be 2
2+4=6