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Tanzania [10]
3 years ago
5

John got a 76, 68, and 83 on his first three test. What score does he need on his fourth test to achieve an 80 average?

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0
It's 93.
simple calculate it by:
(76+68+83+x)/4=80
then 73*5-(67+75+73+69)=x
where x here is the grade needed to reach an av. of 80. 4 is the number of tests.
*common answer*
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Hello Kids! Its Joe giving out a free brainliest to whoever answers this first with the abc's backwards!
sveticcg [70]

Answer:

Z, Y, X,

W, V,

U, T, S, R, Q, P, O, N,

M, L, K,

J, I, H,

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C, B, and A;

Step-by-step explanation:

5 0
2 years ago
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Find the area of quadrilateral with vertices at points (3,0)(4,5)(-1,4)(-2,-1)
guapka [62]

Answer: 20

Step-by-step explanation:

Let 's complete our quadrilateral to a rectangle ; and subtract from it the area highlighted in red

\displaystyle \rm S_{\diamond}=6\cdot 5 =30 \\\\ S_{ABCD}=30-(5:2+5:2+5:2+3:2+1\cdot1)=30-(7,5+1,5+1)=\\\\30-10=20 \\\\ S_{ABCD}=20

4 0
3 years ago
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Brad has eight more nickels than quarters. Altogether he has $6.10. how many of each does he have
wlad13 [49]

Brad have 19 quarters and 27 nickels.

Step-by-step explanation:

Given,

Total worth of nickels and quarters = $6.10 = 6.10*100 = 610 cents

One quarter = 25 cents

One nickel = 5 cents

Let,

x represent the number of quarters.

y represent the number of nickels.

According to given statement;

25x+5y=610     Eqn 1

y = x+8              Eqn 2

Putting value of y from Eqn 1 in Eqn 2

25x+5(x+8)=610\\25x+5x+40=610\\30x=610-40\\30x=570

Dividing both sides by 30

\frac{30x}{30}=\frac{570}{30}\\x=19

Putting x=19 in Eqn 2

y=19+8\\y=27

Brad have 19 quarters and 27 nickels.

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/9369548
  • brainly.com/question/9328925

#LearnwithBrainly

7 0
3 years ago
What is the value of x in this proportion?
astra-53 [7]

Answer:

  (a)  x=−20 1/2

Step-by-step explanation:

Multiply by the product of the denominators and solve the resulting linear equation in the usual way.

  \dfrac{2}{7}=\dfrac{-5}{x+3}\\\\2(x+3)=-5(7)\qquad\text{multiply by $7(x+3)$}\\\\2x+6=-35\qquad\text{simplify}\\\\2x=-41\qquad\text{subtract 6}\\\\\boxed{x=-20\dfrac{1}{2}}\qquad\text{divide by 2}

6 0
2 years ago
A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

A=\pi r^{2}

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

6 0
3 years ago
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