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torisob [31]
3 years ago
10

Assume the availability of class named IMath that provides a static method, toThePowerOf which accepts two int arguments and ret

urns the value of the first parameter raised to the power of the second.An int variable cubeSide has already been declared and initialized. Another int variable, cubeVolume, has already been declared.Write a statement that calls toThePowerOf to compute the value of cubeSide raised to the power of 3 and that stores this value in cubeVolume.
Computers and Technology
1 answer:
geniusboy [140]3 years ago
4 0

Answer:

cubeVolume = IMath.toThePowerOf(cubeSide, 3);

Explanation:

Following is the explanation for above statement:

Left side:

cubeVolume is a variable with data-type int, it will store the integer value that is the output from right side.

Right side:

  • IMath is the class name.
  • toThePowerOf is the built-in function that takes two arguments of data type int. First is the base and second is the power(exponent) separated by comma. In place of first argument that is the base variable we will pass the variable cubeSide that has been declared and initialize.
  • Now the output will be stored in the variable cubeVolume.

i hope it will help you!

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shusha [124]

Answer:

UI Character Presets

Explanation:

User Interface is an option or go-to menu in a desktop application. For example, Photoshop. It allows a user to tweak the outlook to his or her own preference rather than the default settings.

To do this, a user is often tasked to do the following:

1. Click on the "Edit" menu

2. Navigate and click on "Preferences"

3. Select the "Interface" link

The options available to change includes:

a. UI Scaling

b. UI Font Size

c. UI Language.

Hence, in this case, the element that is not a selection in the Interface preferences is "UI Character preset"

7 0
3 years ago
Look at the following code.int x = 7;int *iptr = &x;What will be displayed if you send the expression *iptr to cout ? What h
masha68 [24]

Answer:

The answer to the given question can be given as:

The value of *iptr is 7. and the value of iptr is dynamic.

Explanation:

In the c++ code, it is defined that x is an integer variable that assigns a value which is 7. Then we define a pointer variable that is *iptr. This variable holds an address of the x variable. When we print the value of the iptr variable. if we use the expression *iptr to print value of the pointer variable by cout that is used in c++ for pint values. so the value of the iptr is 7. If we use the expression iptr sent to cout so we show the address of the variable x. In the pointer, it manages the addresses of dynamically allocated so the address of the variable is changed on execution time.

4 0
3 years ago
Write a calculator program that will allow only addition, subtraction, multiplication & division. Have the
ozzi

num1 = float(input("Enter the first number: "))

num2 = float(input("Enter the second number: "))

operation = input("Which operation are you performing? (a/s/m/d) ")

if operation == "a":

   print("{} + {} = {}".format(num1, num2, num1+num2))

elif operation == "s":

   print("{} - {} = {}".format(num1, num2, num1-num2))

elif operation == "m":

   print("{} * {} = {}".format(num1, num2, num1*num2))

elif operation == "d":

   print("{} / {} = {}".format(num1, num2, num1/num2))

I hope this helps!

8 0
2 years ago
A regular language can not be infinite.<br> True<br> False
Elan Coil [88]

Answer:

False

Explanation:

A regular language can be represented by a regular expression. A regular language can be infinite. Let us consider a simple example of an infinite regular language:

a* is a regular language represented by a regular expression.

The languages matches all strings containing or more a's.

Clearly this is an infinite language.

Note that all finite languages are regular but all regular languages need not be finite.

3 0
3 years ago
After establishing a long term goal and understanding what it entails, the best next step is
Aleks [24]

Answer:

plan numerous intermediate short-term goals.

Explanation:

8 0
2 years ago
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