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torisob [31]
3 years ago
10

Assume the availability of class named IMath that provides a static method, toThePowerOf which accepts two int arguments and ret

urns the value of the first parameter raised to the power of the second.An int variable cubeSide has already been declared and initialized. Another int variable, cubeVolume, has already been declared.Write a statement that calls toThePowerOf to compute the value of cubeSide raised to the power of 3 and that stores this value in cubeVolume.
Computers and Technology
1 answer:
geniusboy [140]3 years ago
4 0

Answer:

cubeVolume = IMath.toThePowerOf(cubeSide, 3);

Explanation:

Following is the explanation for above statement:

Left side:

cubeVolume is a variable with data-type int, it will store the integer value that is the output from right side.

Right side:

  • IMath is the class name.
  • toThePowerOf is the built-in function that takes two arguments of data type int. First is the base and second is the power(exponent) separated by comma. In place of first argument that is the base variable we will pass the variable cubeSide that has been declared and initialize.
  • Now the output will be stored in the variable cubeVolume.

i hope it will help you!

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3 years ago
Ask the user to input their grade percentage (e.g. the use will enter 98 if they had an overall grade of 98% in their course) fo
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Answer:

In Python

def getpointValue(subject):

   if subject >= 75:        point = 4; grade = 'A'

   elif subject >= 60:        point = 3; grade ='B'

   elif point >= 50:        point = 2; grade = 'C'

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subjects= ["Accounting","Marketing","Economics","MIS"]

acct = int(input(subjects[0]+": "))

mkt = int(input(subjects[1]+": "))

eco = int(input(subjects[2]+": "))

mis = int(input(subjects[3]+": "))

acctgrade = getpointValue(acct)

print(subjects[0]+" Grade: "+str(acctgrade[1]))

mktgrade = getpointValue(mkt)

print(subjects[1]+" Grade: "+str(mktgrade[1]))

ecograde = getpointValue(eco)

print(subjects[2]+" Grade: "+str(ecograde[1]))

misgrade = getpointValue(mis)

print(subjects[3]+" Grade: "+str(misgrade[1]))

totalpoint = (acctgrade[0] + mktgrade[0] + ecograde[0] + misgrade[0]) * 3

gpa = totalpoint/12

print("GPA: "+str(gpa))

Explanation:

<em>The solution I provided uses a function to return the letter grade and the point of each subject</em>

<em>I've added the explanation as an attachment where I used comment to explain difficult lines</em>

<em />

Download txt
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Answer:

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