Answer:
A motherboard is the main printed circuit board in general-purpose computers and other expandable systems. It holds and allows communication between many of the crucial electronic components of a system
Explanation:
Answer:
The program to this question can be given as:
Program:
#include <stdio.h> //include header file.
int main() //defining main method
{
char i,j; //defining variable
for (i='a'; i<='e'; i++) //outer loop for column
{
for (j='a'; j<='e'; j++) //inner loop for row
{
printf("%c%c\n",i,j); //print value
}
}
return 0;
}
Output:
image.
Explanation:
- In the above C language program, firstly a header file is included. Then the main method is defined in this, a method contains a char variable that is "i and j". This variable is used in for loop, that is used to print the pattern.
- To print the following patter two for loop is used the outer loop is used for print columns and the inner loop prints row.
- In C language to print character, we use "%c" inside a loop print function is used, that prints characters.
Answer:
Output:
15
20
25
Explanation:
In first iteration value of num is 10. Condition is checked 10 is less than 21 so value of num is incremented by 5 and value 15 is printed than again condition is checked 15<21 so value of num is incremented again and 20 is printed. Again condition is checked 20<21. So 25 is printed. Then 4th time when condition is checked vakue of num is 25 and while loop condition becomes false because 25 is not less than 21 and program is terminated here.
Answer:
Running RECURSIVE-MATRIX-CHAIN is asymptotically more efficient than enumerating all the ways of parenthesizing the product and computing the number of multiplications of each.
the running time complexity of enumerating all the ways of parenthesizing the product is n*P(n) while in case of RECURSIVE-MATRIX-CHAIN, all the internal nodes are run on all the internal nodes of the tree and it will also create overhead.
Explanation:
Answer:
Following are the solution to the given choices:
Explanation:
Given:
double currentBalance[91];//defining a double array
In point a:
The name of the array is= currentBalance.
In point b:
91 double values could be saved in the array. It requires 8bytes to hold a double that if the array size is 91*8 = 728
In point c:
Each element's data type is double.
In point d:
The array index range of values is between 0 and 90 (every array index starts from 0 and ends in N-1, here N=91).
In point e:
To access first element use currentBalance[0], for middle currentBalance[91/2] , for last currentBalance[90]