Alrighty, so, 9 less hints to subtract. The product of 37 and x means that you're multiplying 37 and x. Therefore, I believe the answer that you're looking for is 37x-9.
Hope this helps! (:
0.91÷-0.13
=-7
hope this helps!
Answer: 1. ∠A= 80.75° 2. 41.79 
Step-by-step explanation:
Since, According to the sines low,
Here, CB= 4.1 cm, AB = 3.3 and ∠ C = 52.6°
⇒ 
⇒ 
⇒ A = 80.75°
2. Since, the area of the given figure = Area of the rectangle having dimension 8.3 × 4.2 + Area of the half square of radius 2.1
=34.86 + 6.93
= 41.79 square cm
Answer:
CD = 16.5
Step-by-step explanation:
To find the distance between two points, use this formula: 
point C can be info set 1: (10, -1) x₁ = 10 y₁ = -1
point D can be info set 2: (-6, 3) x₂ = -6 y₂ = 3
Substitute the information into the formula
Simplify inside each bracket
Square the numbers
Add inside the root
Enter into calculator
Rounded to the nearest tenth, the first decimal
The distance CD is 16.5.
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
