When x = 2,what is the value of y for the equation – 3x + 2y = 10?

2 answers:

dexar [7]3 years ago

8 0

Answer:

$\huge{ \boxed{ \bold{ \tt{y = 8}}}}$

☪ What is the value of y for the equation given below when x = 2 ?

☪ Step - by - step explanation :

plug the value of x ( i.e 2 )

➳ $\sf{ - 3 \times 2 + 2y = 10}$

Remember : Multiplying or dividing a negative integer by a positive integer gives a negative integer.

➳ $\sf{ - 6 + 2y = 10}$

Move 6 to right hand side and change it's sign

➳ $\sf{2y = 10 + 6}$

Add the numbers : 10 and 6

➳ $\sf{2y = 16}$

Divide both sides by 2

➳ $\sf{ \frac{2y}{2} = \frac{16}{2}}$

➳ $\boxed{ \sf{y = 8}}$

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✏ Now, let's check whether the value of y is 8 or not !

✑ Verification :

$\sf{ - 3x + 2y = 10}$

→ $\sf{ - 3 \times 2 + 2 \times 8 = 10}$

→ $\sf{ - 6 + 16 = 10}$

→ $\sf{10 = 10}$

L.H.S = R.H.S ( Hence , the value of y is 8 . )

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☞ Additional Info :

✒ Sign rules of addition and subtraction of integers:

The positive integers are always added and posses the positive ( + ) sign.
The negative integers are always added but posses the negative ( - ) sign.
The negative and positive integers are always subtracted but posses the sign of the bigger integer.

✒ Sign rules of multiplication and division of integers :

Multiplying or dividing positive integers gives a positive integer.
Multiplying or dividing positive integer by any negative integer gives a negative integer.
Multiplying or dividing a negative integer by a positive integer gives a negative integer.
Multiplying or dividing a negative integer by a negative integer gives a positive integer.

✒ Rules for solving an equation :

If any equation contains fractions , multiply each term by the LCM of denominators.
Remove the brackets , if any.
Collect the term with the variable to the left hand side and constant terms to the right side by changing their signs ' + ' into ' - ' and ' - ' into ' + '.
Simplify and get the single term on each side.
Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Have a wonderful time ツ

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