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inna [77]
3 years ago
11

Explain what a, h, and k do to transform the following equation. Be sure to mention the shift or transformation each variable do

es and how if each varible is a positive or negative : y= a|x-h|+k.​
Mathematics
2 answers:
dangina [55]3 years ago
3 0

Answer:

a: vertical stretch

h: horizontal translation (remember not to get signs mixed up!)

k: vertical translation

Lady_Fox [76]3 years ago
3 0

Explanation:

A → Whether opens down or up; fractions [vertical shrink], whole numbers [vertical stretch]

-H → OPPOSITE terms of what they really are [phase shift]

K → NORMAL term [vertical shift]

I am joyous to assist you anytime.

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Solve the equation 4(x - 1) = 13 for x​
Masja [62]
Answer x=4.25 or 4 1/4
8 0
3 years ago
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you are drawing a map. two cities on the map are 7 inches apart. you know the actual distance between them is 1,750 miles. what
MakcuM [25]

Hello betzy166817!

The correct answer is: <u>250 miles per inch.</u>

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4 0
3 years ago
(-----×1/4)÷6×3/9 I need the step to this problem so that I explain to my grandson how he he gets the answer
lesya692 [45]

Answer:

-----×1/72

Step-by-step explanation:

The <em>order of operations</em> says do these operations in order left to right. Please note that ÷ means the same as / unless you define it otherwise in your problem statement.

If you intend the ÷ symbol to be used to indicate everything to its left is divided by everything to its right, it is appropriate to use parentheses for that grouping, as in ...

  (-----×1/4)÷(6×3/9) = (-----×1/4)÷2 = -----×1/8

_____

Here, we're going to evaluate what you have written according to the usual rules as described above.

  (-----×1/4)÷6×3/9 = -----×1/24×3/9 = -----×(3/24)/9

  = -----×1/8/9

  = -----×1/72

_____

<em>Comment on the arithmetic</em>

Fractions are multiplied and divided in the usual way:

  a/b×c = (a×c)/b

  a/b/c = (a/b) × (1/c) = a/(b×c)

___

<em>Comment on fractions and parentheses</em>

Please note that parentheses are required on any numerator or denominator that consists of anything other than a single number or variable. (The exception is the case where the numerator is a product, because a·b/c = (a·b)/c with or without the parentheses.)

6 0
4 years ago
What is the integral?
sergij07 [2.7K]
Make the u substitution
u=x^2
du=x dx

it should simplify the problem
7 0
3 years ago
Use a surface integral to find the surface area of the portion of the sphere xUse a surface integral to find the surface area of t
brilliants [131]

Parameterize this surface (call it S) by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos v\,\vec k

with 0\le u\le2\pi and 0\le v\le\dfrac\pi4. The limits on u should be obvious. We find the upper limit for v by solving for v where the sphere and cone intersect:

\begin{cases}x^2+y^2+z^2=1\\z=\sqrt{x^2+y^2}\end{cases}\implies x^2+y^2=\dfrac12

\implies(\cos u\sin v)^2+(\sin u\sin v)^2=\dfrac12

\implies\sin^2v=\dfrac12

\implies\sin v=\dfrac1{\sqrt2}\implies v=\dfrac\pi4

Take the normal vector to S to be

\vec r_u\times\vec r_v=-\cos u\sin^2v\,\vec\imath-\sin u\sin^2v\,\vec\jmath-\cos v\sin v\,\vec k

(orientation does not matter here)

Then the area of S is

\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{\pi/4}\int_0^{2\pi}\sin v\,\mathrm du\,\mathrm dv

=\displaystyle2\pi\int_0^{\pi/4}\sin v\,\mathrm dv=\boxed{(2-\sqrt2)\pi}

4 0
3 years ago
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