(y1 - y2) / (x1 - x2) = slope
(-1 - 3) / (4 - 2)
-4 / 2
<em>-2</em>
Hope this helps! :)
Step-by-step explanation:
1st year interest calculated = 3.25/100 × $4500/1 = $146.25
2nd year principal = 1st year principal + 1st year interest = $4500 + $146.25 = $4646.25. 2nd year interest calculated = 3.25/100 ×$4646.25/1 =$151
3rd year principal = 2nd principal + 2nd year interest = $4646.25 + $151 = $4797.25. 3rd year interest calculated = 3.25/100 × $4797.25/1 = $155.91
4th year principal = 3rd year principal + 3rd year interest =$4797.25 + $155.91 =$4953.16. 4th year principal calculated = 3.25/100 × 4953.16/1 =$160.98
5th year principal = 4th year principal + 4 year interest = &4953.16 +$160.98 = $5114.14. 5th year interest calculated = 3.25/100 × 5114.14/1 =$166.21
6th year principal =5th year principal + 5th year interest = $5114.14 + $166.21 =$5280.35. 6th year interest calculated = 3.25/100 × 5280.35/1 =$171.61
Amount = main principal + compound interest =$4500 +&146.25 +$151+$155.91+$160.98+$166.21+$171.61 =$5451.96
Answer:
b) 94
Step-by-step explanation:
The Total Degree of a Triangle is 180 degrees. Knowing this, set up an equation.
68+26+x=180.
x is the complementary angle of the "?" angle.
Solve the equation.
94+x=180
x=86
Then Subtract 86 from 180 to find "?"
180-86=94
I hope this helps!
Answer:
At a point when r = 6 ft
The rate of change of Area with time is given as
(dA/dt) = 36π = 113.1 ft²/min
Step-by-step explanation:
Area of a circle, A = πr²
A = πr²
(dA/dt) = (dA/dr) × (dr/dt)
(dA/dr) = 2πr, (dr/dt) = 3
(dA/dt) = 2πr × 3 = 6πr
At a point when r = 6 ft
(dA/dt) = 6πr = 6π × 6 = 36π = 113.1 ft²/min
First, coordinate Q is (-5,2) and Q' is (6,2). First, we know that this is a horizontal reflection becuase only the x-values change. This means that the line of reflection will be x=some value. I think the best way to go about this is to find the midpoint of Q and Q' using the formula: M=(x1+x2/2,y1+y2/2)
Q is the first point and Q' is the second point
M=(-5+6/2,2+2/2)
M=(1/2,4/2)
M=(1/2,2)
Since we know the y-values of Q, Q', and the midpoints are all 2, then the line of reflection would be x=1/2
Hope this helps
