All categories

3 years ago

Correct answers only please!

Mathematics

2 answers:

aliya0001 [1]3 years ago

6 0

Answer:

C. 0.883

Step-by-step explanation:

58 + 2(24) + 3(8) + 4(39) / 324

0.8827

Irina18 [472]3 years ago

6 0

Answer:

C. 0.883

Step-by-step explanation:

A player has 58 singles, 24 doubles, 8 triples, and 39 home runs, with 324 At bats. The formula for a baseball player's slugging percentage is 0.883.

You might be interested in

Four rats are selected at random from a cage of 5 male (M) and 6 female (F) rats. If the random variable Y is concerned with the

Ludmilka [50]

Using the hypergeometric distribution, it is found that the distribution is:

P(X = 0) = 0.0152

P(X = 1) = 0.1818

P(X = 2) = 0.4545

P(X = 3) = 0.3030

P(X = 4) = 0.0455

Hence:

A) There is a 0.0455 = 4.55% probability that all selected rats are female.

B) There is a 0.1818 = 18.18% probability that only one of the selected rats is female.

C) There is a 0.803 = 80.3% probability that at least two of the selected rats is female.

D) The mean of the probability distribution is of 2.18.

E) The standard deviation of the probability distribution is of 0.833.

The rats are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

There is a total of 11 rats, hence N = 11.

6 of the rats are female, hence k = 6.

4 rats are taken, hence n = 4.

The distribution is the probability of each outcome, hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,11,4,6) = \frac{C_{6,0}C_{5,4}}{C_{11,4}} = 0.0152$

$P(X = 1) = h(1,11,4,6) = \frac{C_{6,1}C_{5,3}}{C_{11,4}} = 0.1818$

$P(X = 2) = h(2,11,4,6) = \frac{C_{6,2}C_{5,2}}{C_{11,4}} = 0.4545$

$P(X = 3) = h(3,11,4,6) = \frac{C_{6,3}C_{5,1}}{C_{11,4}} = 0.3030$

$P(X = 4) = h(4,11,4,6) = \frac{C_{6,4}C_{5,0}}{C_{11,4}} = 0.0455$

Item a:

P(X = 4) = 0.0455, hence:

There is a 0.0455 = 4.55% probability that all selected rats are female.

Item b:

P(X = 1) = 0.1818, hence:

There is a 0.1818 = 18.18% probability that only one of the selected rats is female.

Item c:

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.4545 + 0.3030 + 0.0455 = 0.803$

There is a 0.803 = 80.3% probability that at least two of the selected rats is female.

Item d:

The mean of the hypergeometric distribution is:

$\mu = \frac{nk}{N}$

Hence:

$\mu = \frac{4(6)}{11} = 2.18$

The mean of the probability distribution is of 2.18.

Item e:

The standard deviation of the hypergeometric distribution is:

$\sigma = \sqrt{\frac{nk(N-k)(N-n)}{N^2(N-1)}}$

Hence:

$\sigma = \sqrt{\frac{4(6)(11-6)(11-4)}{11^2(11-1)}} = 0.833$

The standard deviation of the probability distribution is of 0.833.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

5 0

2 years ago

HELP DUE IN 10 MINUTES WILL GIVE BRAINLEST!!

True [87]

$\\ \bull\longmapsto 4x-1=3y+5$

$\\ \bull\longmapsto 4x-3y=6$

X. intercept

$\\ \bull\longmapsto 4x=6+3y\implies x=\dfrac{3y+6}{4}$

Now

Put 0 on y

$\\ \bull\longmapsto x=\dfrac{3(0)+6}{4}=\dfrac{6}{4}=\dfrac{3}{2}$

Hence

$\\ \bull\longmapsto x-intercept=\left(\dfrac{3}{2},0\right)$

Y intercept:-

$\\ \bull\longmapsto 3y=4x-6\implies y=\dfrac{4x-6}{3}$

Put 0 on x

$\\ \bull\longmapsto y=\dfrac{4(0)-6}{3}=\dfrac{-6}{3}=-2$

Hence.

$\\ \bull\longmapsto y-intercept=(0,-2)$

8 0

3 years ago

150m - 100m + 47.750 = 50.500- 200m

coldgirl [10]

Answer:

m=11÷600

Step-by-step explanation:

150m-100m+47.750=50.5000-200m

collect the like terms

-50m+47.75=50.5-200m

move variable to the left side and change its sign

-50m+200m+47.75=50.5

Move constant to the right side and change its sign

50m+200m=50.5-47.75

collect the like terms(again)

150m=50.5-47.75

subtract the numbers

150m=2.75

divied both sides of the equation by 150

m=11÷600

solution

m=11÷600

alternative form

m=0.0183

5 0

3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually g

inna [77]

Answer:

D. It would be less steep

Step-by-step explanation:

The first graph moves at a rate of 5/1 which is a greater fraction than 3/4

The second graph is shallow due to the close points in x and y that are able to be conducted
The first Graph rapidly increases at a way higher rate making it VERY steep
While both are linear the second strays away in terms of plot lines

7 0

4 years ago

Work out the percentage change to 2 decimal places when a price of £110 is<br> decreased to £98.

djyliett [7]

Answer:

10.91% decrease

Step-by-step explanation:

98/110 x 100 = 89.090909

100 - 89.0909 = 10.909090 to 2dp is 10.91%

8 0

3 years ago