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mario62 [17]
3 years ago
9

Which expression is equivalent to.... please help

Mathematics
1 answer:
Margarita [4]3 years ago
4 0
X^2+3x+3+[(2x^2+13+15)/(x+5)] is equivalent to option 4.   im sorry if i got my math wrong but i hope this helps. 
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3 years from now, Ron's age will be 2 times that of Miley. Three years ago, Ron's age was 3 times that of Miley.
andrezito [222]

Answer:

M=9

EXPLANATION:

Let R represent Ronald’s present age. Let M represent Miley’s present age. Three years from now, Ronald and Miley will be R+3 and M+3 years old, respectively.

Your assertion “Three years from now, Ron’s age will be 2 times that of Miley's” can be written as

R + 3 = 2*(M + 3)

Similarly, your assertion “Three years ago, Ron's age was 3 times that of Miley's” can be written as

R - 3 = 3*(M-3)

We can add the left side of these equations together, and also the right side of these equations together, and obtain a new equation …

R + 3 + R - 3 = 2*(M + 3) + 3*(M - 3) = 2M + 6 + 3M - 9 = 5M - 3

This can be simplified to

2R = 5M - 3

We can divide both sides of the last equation by 2, and obtain ..

(2/2) * R = (5/2) * M - 3/2, or R = (5/2) * M - 3/2.

Now we can “plug in” the last equation into either of our first two equations of this post, and solve for M.

Using the first equation, we have

(5/2) * M - 3/2 + 3 = 2 *(M + 3) = 2M + 6

We now have

(5/2) * M + 3/2 = 2M + 6

The left side of this equation can be rewritten as

(5M + 3) / 2, so we obtain

(5M + 3) / 2 = 2M + 6

Multiplying both sides by 2, we have

5M + 3 = 4M + 12

Subtracting 4M and 3 from both sides, we obtain

M = 9

Miley’s present age is 9.

plss give brainliest

3 0
3 years ago
F(x) = 1/3x -2; reflection in the x-axis
san4es73 [151]
Would it be -1/3x -2?
4 0
2 years ago
If 1:2 represents the amount of students that walked and the amount of students that took the subway and 1:3 represent the amoun
vivado [14]

Answer:

If 3 students walked, then according to the given ratios, 18 students would have taken the bus.

Step-by-step explanation:

Given: 3 Walkers

1:2 --> 3:6 walkers to subway

1:3 --> 6:18 subway to bus riders

4 0
3 years ago
The two lines graphed below are not parallel.How many solutions are there to system of equations
nika2105 [10]

we need the graph/ lines,

but just remember

wherever 2 lines intersect, that is a solution

if they are paralell, no solutions

if they cross, 1 solution

if they are the same line/ the lines are on top of each other exactly, infinite solutions

7 0
3 years ago
An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft 3 . Find the d
denpristay [2]

Answer:

The dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

Step-by-step explanation:

Given : An open top box is to be built with a rectangular base whose length is twice its width and with a volume of 36 ft³.

To find : The dimensions of the box that minimize the materials used ?

Solution :

An open top box is to be built with a rectangular base whose length is twice its width.

Here, width = w

Length = 2w

Height = h

The volume of the box V=36 ft³

i.e. w\times 2w\times h=36

h=\frac{18}{w^2}

The equation form when top is open,

f(w)=2w^2+2wh+2(2w)h

Substitute the value of h,

f(w)=2w^2+2w(\frac{18}{w^2})+2(2w)(\frac{18}{w^2})

f(w)=2w^2+\frac{36}{w}+\frac{72}{w}

f(w)=2w^2+\frac{108}{w}

Derivate w.r.t 'w',

f'(w)=4w-\frac{108}{w^2}

For critical point put it to zero,

4w-\frac{108}{w^2}=0

4w=\frac{108}{w^2}

w^3=27

w^3=3^3

w=3

Derivate the function again w.r.t 'w',

f''(w)=4+\frac{216}{w^3}

For w=3, f''(3)=4+\frac{216}{3^3}=12 >0

So, it is minimum at w=3.

Now, the dimensions of the box is

Width = 3 ft.

Length = 2(3)= 6 ft

Height = \frac{18}{3^2}=2\ ft

Therefore, the dimensions of the box that minimize the materials used is 6\times 3\times 2\ ft

4 0
3 years ago
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