Answer:
y = 1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
-3y + 14 + y = 12
<u>Step 2: Solve for </u><em><u>y</u></em>
- Combine like terms [Addition]: -2y + 14 = 12
- [Subtraction Property of Equality] Subtract 14 on both sides: -2y = -2
- [Division Property of Equality] Divide -2 on both sides: y = 1
Answer:
Option A: 3x + 5x - 4 = 1
Step-by-step explanation:
Given that:
3x + y = 1 ------------- eq1
y + 4 = 5x ------------ eq2
Now for substitution in eq1 we will get a value of y from eq2:
y = 5x - 4
Substituting in eq1 we get:
3x + 5x - 4 = 1
i hope it will help you!
12 5/10 вecaυѕe ιғ yoυ тυrn тнe ғracтιon вacĸ тo a decιмal ιт woυld вe 5.0 dιvιded вy 10 woυld eqυal 12. 5
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
13.8%
Step-by-step explanation:
P = nCr pʳ qⁿ⁻ʳ
P = ₉C₅ (0.37)⁵ (1−0.37)⁹⁻⁵
P ≈ 0.138
