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bazaltina [42]
3 years ago
14

A person is 2 meters tall casts a shadow 6 meters long. At the same time, a flagpole casts a shadow 24 meters long. How tall is

the
flagpole?
2m
бm
24m
Mathematics
1 answer:
Alexandra [31]3 years ago
4 0

Answer:

8 meters

Step-by-step explanation:

Given that:

Height of person = 2metres

Length of person's shadow = 6 meters

Height of flagpole =?

Length of flagpole shadow = 24 meters

Height of person = length of person's shadow

Height of flagpole = length of person's shadow

2 = 6

x = 24

Cross multiply

6x = 48

x = 48 / 6

x = 8 meters

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Write an ordered pair for each point graphed below.
Viefleur [7K]

Answer:

\boxed{(-1,4)}

Step-by-step explanation:

The point is located in Quadrant II of the graph, where x-values are negative and y-values are positive.

Each marking on the graph represents one unit of distance. The two <em>axes</em> meet at the origin, where the coordinate point is equal to (0,0).

So, you can count backwards once from the origin to get your x-value ⇒ -1 and count up upwards four times from x=-1 to get your y-value ⇒ 4.

Finally, place these in a coordinate point (x,y) ⇒ \boxed{(-1,4)}.

5 0
3 years ago
Read 2 more answers
Fred and Ben each ran laps around the track. Fred completed his run in 16 minutes. Ben completed his run in 3/4 of the amount of
m_a_m_a [10]

Answer:

Time required by Ben was 12 minutes.

Step-by-step explanation:

Given:

Time Required for Fred = 16 mins

Ben completed his run in 3/4 of the amount of time of Freds run.

We need to find the time required by Ben.

Now Given that;

Ben completed his run in 3/4 of the amount of time of Freds run.

It means that time required by Ben is equal to 3/4  times time required by Fred.

Time required by Ben = \frac{3}{4}\times  Freds \ run

Time required by Ben = \frac{3}{4}\times 16 = 12\ mins

Hence Time required by Ben was 12 minutes.

7 0
3 years ago
3.Write the product as a trinomial. (2r – 5)(r + 10)
Maurinko [17]
B is the correct answer

5 0
3 years ago
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• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando
antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:  

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$ Z =  \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}  $

$ Z =  \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}  $

$ Z =  \frac{- 0.09}{ 0.048989 }  $

Z = - 1.84

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p >  α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0
3 years ago
I need help please hurry.
Anarel [89]

Answer:the answer is the first

Step-by-step explanation:

Because the expression can be written as -10r2/2r2+4+5r/2r2+4+3/2r2+4

8 0
3 years ago
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