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maxonik [38]
3 years ago
6

Magnetic force... Is it a Conservative or Non-conservative field?

Physics
1 answer:
solniwko [45]3 years ago
4 0
The correct answer is non-conservative

This is bewildering to people, however, since it shows that it has many aspects of a conservative fields, but is technically not one.
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How can you measure the strength of any electric field?
Softa [21]

Answer:

The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q.

Explanation:

Electric field strength is a vector quantity; it has both magnitude and direction. The magnitude of the electric field strength is defined in terms of how it is measured. Let's suppose that an electric charge can be denoted by the symbol Q. This electric charge creates an electric field; since Q is the source of the electric field, we will refer to it as the source charge. The strength of the source charge's electric field could be measured by any other charge placed somewhere in its surroundings. The charge that is used to measure the electric field strength is referred to as a test charge since it is used to test the field strength. The test charge has a quantity of charge denoted by the symbol q. When placed within the electric field, the test charge will experience an electric force - either attractive or repulsive. As is usually the case, this force will be denoted by the symbol F. The magnitude of the electric field is simply defined as the force per charge on the test charge.

7 0
3 years ago
The potential energy of a particle as a function of position will be given as U(x) = A x2 + B x + C, where U will be in joules w
satela [25.4K]

Answer:

F = - 2 A x - B

Explanation:

The force and potential energy are related by the expression

      F = - dU / dx i ^ -dU / dy j ^ - dU / dz k ^

Where i ^, j ^, k ^ are the unit vectors on the x and z axis

The potential they give us is

     U (x) = A x² + B x + C

Let's calculate the derivatives

    dU / dx = A 2x + B + 0

The other derivatives are zero because the potential does not depend on these variables.

Let's calculate the strength

      F = - 2 A x - B

3 0
3 years ago
Can someone help check question 2 I don’t think part 2 is right?!
Alisiya [41]
Your answer for question two is right
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Select the statement that best describes how the forces relate. A. All forces begin equally and become varied. B. The object on
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Electromagnetic and Gravitational forces are most alike because their range is not limited. 
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4 years ago
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What phase is the Moon in when it appears completely dark?
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New Moon appears completely dark
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