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maxonik [38]
3 years ago
6

Magnetic force... Is it a Conservative or Non-conservative field?

Physics
1 answer:
solniwko [45]3 years ago
4 0
The correct answer is non-conservative

This is bewildering to people, however, since it shows that it has many aspects of a conservative fields, but is technically not one.
You might be interested in
State the name of electromagnetic wave other than visible light ?​
Natali5045456 [20]

Answer:

-Radio waves

-Microwaves

-Infrared light (IR)

-Visible light

-Ultraviolet (UV)

-X-ray

-Gamma rays

(this is in order from the longest wavelength to shortest wavelength)

7 0
3 years ago
Two identical ambulances with loud sirens are driving directly towards you at a speed of 40 mph. One ambulance is 2 blocks away
Rasek [7]

Answer:

c) The pitch of the two sirens sounds the same to you

Explanation:

The pitch does not depend on the distance of the object from the observer.

As per the given data

pitch = frequency

Frequency = f_{0}  \frac{V +- V_{0}}{V +- V_{s}}

f^{'} = f_{0}  \frac{V }{V - V_{s}}

Hence, the pitch of the two sirens remains the same for the observer.

5 0
3 years ago
Read 2 more answers
A scuba diver, submerged under water looks up and seessunlight
maw [93]

Answer:

41.7975\ ^{\circ}

Explanation:

n_2 = Refraction index of water = 1.333

n_1 = Refraction index of air = 1

\theta_2 = Angle of sunlight = 30°

From Snell's law we have

\dfrac{n_1}{n_2}=\dfrac{sin\theta_2}{sin\theta_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{n_2sin\theta_2}{n_1}\\\Rightarrow \theta_1=sin^{-1}\dfrac{1.333sin30}{1}\\\Rightarrow \theta_1=41.7975\ ^{\circ}

The angle measured from the vertical does the sunlight strike thesurface of the water is 41.7975\ ^{\circ}

5 0
3 years ago
Suppose that a parallel-plate capacitor has circular plates with radius R = 25 mm and a plate separation of 4.7 mm. Suppose also
ozzi

Answer:

a) B_{max} = 1.784*10^{-12}

Explanation:

Given paraeters are:

R = 25 cm

d = 4.7 mm

f = 60 Hz

V_m = 160 V

a) V = V_msin(2\pi ft)

Where f = 60 Hz and V_m = 160 V

E =V/d= \frac{V_msin(2\pi ft)}{d}

For r = R

A = \pi R^2

Since \Phi_E = EA

\Phi_E=\frac{\pi R^2V_msin(2\pi ft) }{d}

From Ampere's Law:

\int B.ds = \mu_0\epsilon_0\frac{d\Phi_E}{dt} + \mu_0I_{encl} where I_{encl}=0

So at r = R,

B.2\pi R = \mu_0\epsilon_0\frac{d\Phi_E}{dt}\\B.2\pi R = \mu_0\epsilon_0\frac{2\pi^2fR^2V_mcos(2\pi ft)}{d}\\B = \frac{\mu_0\epsilon_0\pi fRV_mcos(2\pi ft)}{d}

For maximum B, cos(2πft) = 1. Hence,

B_{max}=\frac{\mu_0\epsilon_0\pi fRV_m}{d}=\frac{4\pi*10^{-7}*8.85*10^{-12}*\pi*60*0.025*160}{4.7*10^{-3}}=1.784*10^{-12} T

b) From r = 0 to r = R = 0.025 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fR^2V_m}{rd}

From r = R = 0.025 m to r = 0.1 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fRV_m}{d}

The plot is given in the attachment.

5 0
4 years ago
You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizonta
Citrus2011 [14]

Answer:

\triangle x=3.2*10^-^5 m

Explanation:

From the question we are told that

Height of circular cylinder is h= 1.8m

Diameter of cylinderD=4cm=>0.04m

Horizontal Force  F=900N

Y = 10.0 *10^1^0 N/m^2 \\B = 9.0 * 10^1^0 N/m^2\\S = 4.0 * 10^1^0 N/m^2\\

Generally the formula for shear modulus is mathematically represented by

G=\frac{\tau}{\gamma}

Where

G=Shear modulus\\\tau= shear\ stress\\\gamma=shear strain

G=\frac{F/A}{\triangle x/L}

G=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900/\pi r^2}{\triangle x/1.8}

4.0*10^1^0=\frac{900}{\pi r^2}  *\frac{1.8}{\triangle x}

{\triangle x} =\frac{1620}{\pi r^2* 4.0*10^1^0}

\triangle x=3.2*10^-^5 m

5 0
3 years ago
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