to start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 53.0° above the ho
1 answer:
You might be interested in
A)
The strength of the magnetic field produced by a current-carrying wire is given by
where
is the vacuum permeability
I is the current in the wire
r is the distance from the wire
In this situation,
I = 5.20 A
r = 4.60 cm = 0.046 m is the distance of the electron from the wire
Therefore the magnetic field strength at the electron's location is
The force exerted on a charged moving particle travelling perpendicular to a magnetic field is given by
where
q is the magnitude of the charge of the particle
v is its velocity
B is the magnetic flux density
For the electron of this problem,
is the charge
is the speed
is the magnetic field
Substituting,
B) Same direction as the current in the wire
First of all we have to find the direction of the magnetic field lines, which are concentric around the wire. Assuming the wire carries a current pointing upward, then if we use the right-hand rule:
- The thumb gives the direction of the current -> upward
- The other fingers wrapped give the direction of the field lines -> anticlockwise around the wire (as seen from top)
Now the direction of the force can be found by using the right-hand rule. We have:
- direction of the index finger = direction of motion of the electron (toward the wire, let's assume from east to west)
- middle finger = direction of the magnetic field (to the north)
- Thumb = direction of the force --> downward
However, the electron carries a negative charge, so we must reverse the direction of the force: therefore, the force experienced by the electron will be upward, so in the same direction as the current in the wire.
Answer:
Explanation:
Work is the product of force and distance.
The force is 500 Newtons and the couch is raised 12 meters above the ground.
Substitute these values into the formula.
Multiply.
- 1 Newton meter is equal to 1 Joule.
- So, our answer of 6000 N*m equals 6000 J
The work done to move a 500 Newton couch 12 meters is <u>6000 Joules</u>. Therefore, choice D is correct.
Answer:
1) U = -4.436 10-7 J , 2) r13 = 0.6937 m
Explanation:
The electric potential energy is given by the equation
U = k Σ
/
1. Let's apply this equation to our case
U = k (q1q3 / r13 + q1 q2 / r12 + q2 q3 / r23)
Let's reduce all magnitudes to the SI system
q1 = 4.10 nC = 4.10 10-9 C
q2 = -2.90 nC = -2.90 10-09 C
q3 = 2.00 nC = 2.00 10-9 C
Let's look for the distances
r13 = 11-0 = 11 cm = 11 10-2 m
r12 = 20-0 = 20 cm = 20 10-2 m
r23 = 20 -11 = 9 cm = 9.0 10-2 m
Let's calculate the electric potential
U = 8.99 109 [(4.10 2.00) 10-18 / 11 10-2 + (4.10 (-2.90)) 10-18 / 20 10-2 + (-2.90 2.00) 10-18 / 9.0 10-2]
U = 8.99 [0.7455 - 0.5945 - 0.6444) 10-7
U = -4.436 10-7 J
2. ask to find the position of q3 for the energy to be zero
U = 0 = k (q1q3 / r13 + q1 q2 / r12 + q2 q3 / r23)
In this case the distance between 1 and 2 is fixed, since the load that is placed is 3
q1 q2 / r12 = - q1 q3 / r13 - q2 q3 / r23
-11.89 10-18 / 20 10-2 = -8.20 10-18 / r13 + 5.810-18 / r23
-0.5945 102 = -8.20 / r13 + 5.810 / r23
Let's relate the distances, the maximum separation esr12 which is 20 10-2 m
r12 = r13 + r23
r13 = r12 -r23
r13 = 2010-2 - r23
we replace
-0.5945 102 = -8.20 / (20 10-2 - r23) + 5.810 / r23
Let's solve this equation
-0.5945 102 (2010-2 - r23) = -8.20 r23 + 5.810 (2010-2 - r23)
- 11.89 + 0.5945 r23 = -8.20 r23 + 1,162 - 5,810 r23
-11.89 - 1,162 = - 8.20 r23 -5,810 r23 - 0.5945 r23
-13.052 = r23 (-14.6045)
r23 = 13.052 / 14.6045
r23 = 0.8937 m
The distance from the origin is
r13 = -r12 + r23
r13 = -20 10-2 + 0.8937
r13 = 0.6937 m