Answer:
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Step-by-step explanation:
Given - Azul spun a tri-color spinner twice.
To find - What is the probability that the spinner landed on the colors blue and green in any order?
Solution -
Given that,
A tri-color spinner spun twice
So,
The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}
⇒n(S) = 9
Now,
Let A be an event that the spinner landed on the colors blue and green
So,
A = {BG, GB}
⇒n(A) = 2
Now,
Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)
= 2 ÷ 9
∴ we get
The Probability that the spinner landed on the colors blue and green in any order = 2/9
Remark
Don't try and do this all at once. Break it down, otherwise you'll have layers and brackets all over the place.
Step One
Find 23/0.3
X = 23/0.3 = 76.7
Step Two
Now Divide by 20
x1 = 76.7 / 20
x1 = 3.83
Step Three
Take this result and put it over 24
x2 = x1/24
x2 = 3.83 / 24
x2 = 0.1597 <<<< Answer
3^2+3^2=c^2
18=c^2
c=3sqrt2
Or 4.24 if you need a decimal answer
Answer:
The process of photosynthesis is commonly written as: 6CO2 + 6H2O → C6H12O6 + 6O2.
Step-by-step explanation:
