Answer:
- Josh's book lands first
- Ben's lands about 0.648 seconds later
Step-by-step explanation:
Using the given equation for v=60 and s=40, the height of Ben's book is ...
h(t) = -16t² +60t +40
We want to find t when h(t) = 0, so we're looking for the solution to ....
0 = -16t² +60t +40
Using the quadratic formula, we find the positive value of t to be ...
t = (-60 -√(60² -4(-16)(40)))/(2(-16)) = (15 +√385)/8 ≈ 4.3277
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Similarly, the height of Josh's book is ...
0 = -16t² +48t +40
t = (-48 -√(48² -4(-16)(40)))/(2(-16)) = (12 +√304)/8 ≈ 3.6794
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The time before Josh's book lands is shorter by ...
4.3277 -3.6794 ≈ 0.6482 . . . . . seconds
Josh's book reaches the ground first, by about 0.648 seconds.
there's no exact answer for it because pi goes on forever
y=-1/2x-4
I could be wrong. Not my strong subject.
-Seth
Answer:
Step-by-step explanation:
2 * 10^7 You are to use a single digit. That's the 2 on the left. Then count what it takes to get the decimal between the 2 and the 3. It's 7
0.000136
Count the number of zeros. Add a minus 1. You want the number to be counted until you get minus 1 which is the number of powers after the 1.
1 * 10^-4
26837 becomes 2 * 10^4. 4 is the number of digits you have before you get to a number between 1 and 10.
0.0302 becomes 3 * 10^-(1 + 1) = 3 * 10^-2