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777dan777 [17]
3 years ago
10

Ab|| and b||c so a||c

Mathematics
2 answers:
Veronika [31]3 years ago
8 0

<u><em>*(Explanation)*=</em></u> The reason why it is true is because it is using the transitive property which is a=b and c=d then a=d

<u><em>*(Answer)*=</em></u> True

Hope this helps in anyway

The person who answered: <u><em>BangtanBoyScouts</em></u>

Sindrei [870]3 years ago
5 0

I think it is true. But Please don't take my word on it.

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ASAP!!!!!! show your work plzz!!
Nat2105 [25]
4(p - 7) = 44
First distribute the 4 over the parentheses
4p - 28 = 44
Add 28 to both sides:-
4p = 44 + 28
4p = 72
Divide both sides by 4:-
p = 72/4
p = 18 (answer)
4 0
3 years ago
Solve for x -7 - 4 (2x - 1) = 21
Misha Larkins [42]

Answer:

x=-3

Step-by-step explanation:

-7-4(2x-1)=21

-7-8x+4=21

-7+4-8x=21

-3-8x=21

8x=-3-21

8x=-24

x=-24/8

x=-3

7 0
3 years ago
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5 0
3 years ago
What is the range of the function
balandron [24]

A square root can’t be a negative value, so the root would be greater than or equal to zero.

Range:

Y>=O

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4 0
2 years ago
PLEASE HELP AND ANSWER!!!!! Which of the following reveals the minimum value for the equation 2x2 + 12x − 14 = 0?
NARA [144]

Answer:

The correct option is 3.

Step-by-step explanation:

The given equation is

2x^2+12x-14=0

It can be written as

(2x^2+12x)-14=0

Taking out the common factor form the parenthesis.

2(x^2+6x)-14=0

If an expression is defined as x^2+bx then we add (\frac{b}{2})^2 to make it perfect square.

In the above equation b=6.

Add and subtract 3^2 in the parenthesis.

2(x^2+6x+3^2-3^2)-14=0

2(x^2+6x+3^2)-2(3^2)-14=0

2(x+3)^2-18-14=0

2(x+3)^2-32=0             .... (1)

Add 32 on both sides.

2(x+3)^2=32

The vertex from of a parabola is

p(x)=a(x-h)^2+k        .... (2)

If a>0, then k is minimum value at x=h.

From (1) and (2) in is clear that a=2, h=-3 and k=-32. It means the minimum value is -32 at x=-3.

The equation 2(x+3)^2=32 reveals the minimum value for the given equation.

Therefore the correct option is 3.

5 0
3 years ago
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