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Varvara68 [4.7K]
3 years ago
15

Heyoooo :D

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
8 0

Answer:

D

Step-by-step explanation:

finlep [7]3 years ago
5 0
D or the 4th answer
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Find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126
True [87]

Answer:

Step-by-step explanation:

let the numbers be x,x+1,x+2   (x<x+1<x+2)

2x+3(x+2)=126

2x+3x+6=126

5x=126-6

5x=120

x=120/5=24

numbers are 24,24+1,24+2

or 24,25,26

5 0
3 years ago
2x^2-3x-9 please help
Romashka-Z-Leto [24]
Im assuming you mean 2x^2-3x-9=0 ?
If so, you have to factorise the equation
(2x-3) (x+3) = 0

2x - 3 = 0
2x = 3
x = 1.5

x + 3 = 0
x = -3

x is either 1.5 or -3

8 0
4 years ago
Read 2 more answers
Solve the absolute value equation. If no solution write NO SOLUTION.<br> -{2x + 3] + 8<br> 12
Natasha2012 [34]

Answer:

If problem is "-|2x+3|+8=12"

then there is (<em>no solution.)</em>

Step-by-step explanation:

Let's solve your equation step-by-step.

−|2x+3|+8=12

Step 1: Add -8 to both sides.

−|2x+3|+8+−8=12+−8

−|2x+3|=4

Step 2: Divide both sides by -1.

−|2x+3|=4

   -1       -1

|2x+3|=−4

Step 3: Solve Absolute Value.

|2x+3|=−4

No solutions Because absolute value is less than 0.

4 0
3 years ago
Someone help me with my math homework pleaseee. Find the volumes of the pyramids and the height is 7cm for the first one.
gregori [183]
\bf \textit{volume of a pyramid}\\\\&#10;V=\cfrac{1}{3}Bh\qquad &#10;\begin{cases}&#10;B=\textit{area of the base}\\&#10;h=height&#10;\end{cases}

now, the first one, on the far-left.... can't see the height.. but I gather you do, now as far as its Base area, well, the bottom is just a 12x12 square, so the area of its base is just 12*12


now, the middle pyramid, has a height of 6, the base is also a square, 8x8, so the Base area is just 8*8

now the last one on the far-right

has a height of 8, the Base is a Hexagon, with sides of 6

\bf \textit{area of a regular polygon}\\\\&#10;A=\cfrac{1}{4}ns^2cot\left( \frac{180}{n} \right)\qquad &#10;\begin{cases}&#10;n=\textit{number of sides}\\&#10;s=\textit{length of one side}\\&#10;\frac{180}{n}=\textit{angle in degrees}\\&#10;----------\\&#10;n=6\\&#10;s=6&#10;\end{cases}\\\\\\ A=\cfrac{1}{4}\cdot 6\cdot 6^2\cdot cot\left( \frac{180}{6} \right)
5 0
3 years ago
I need help I don't know how to do this
AveGali [126]

Answer:

Step-by-step explanation:

4 0
3 years ago
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