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laila [671]
3 years ago
5

Which best describes the trends in electronegativity on the periodic table?

Chemistry
2 answers:
Veseljchak [2.6K]3 years ago
8 0
Electronegativity is higher on the right side of the periodic table, such as the noble gasses. There electronegativity is around 3.0 and 4.0 while the left side has electronegativity ranging from .7 to 1.0
Aleksandr-060686 [28]3 years ago
8 0

The correct answer is:

Electronegativity increases up and to the right

Explanation:

Electronegativity, logo χ, is a chemical property that explains the trend of an atom to attract a shared pair of electrons towards itself.As you move from left to right across the periodic table, electronegativity increases, and as you move down the table electronegativity decreases.

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Is it possible for parents whose alleles for a dominant trait are homozygous dominant to have offspring with a homozygous recess
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4 years ago
Name the following chemical compound.
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3 years ago
A container of N2O3(g) has a pressure of 0.265 atm. When the absolute temperature of the N2O3(g) is tripled, the gas completely
Rzqust [24]

Answer:

1.59 atm

Explanation:

The reaction is:

N_{2}O_{3}(g) - - -> NO_{2}(g)+NO(g)

The dalton's law tell us that the total pressure of a mixture of gases is the sum of the partial pressure of every gas.

So after the reaction the total pressure is:

P_{total}=P_{NO_{2}}+P_{NO}

we don't include N_{2}O_{3} because it decomposed completely.

Assuming  ideal gases

PV=nRT

P= pressure, V= volume of the container, n= mol of gas, R=constant of gases and T=temperature.

so moles of N_{2}O_{3} is:

n_{N_{2}O_{3}}=\frac{P_{1}V}{RT_{1}}

from the  reaction stoichiometry (1:1) we have that after the reaction the number of moles of each product is the same number of moles of N_{2}O_{3}.

n_{NO_{2}}=\frac{P_{1}V}{RT_{1}}

n_{NO}=\frac{P_{1}V}{RT_{1}}

The partial pressure of each gas is:

P_{NO_{2}}=\frac{n_{NO_{2}*R*T_{2}}}{V}

P_{NO}=\frac{n_{NO}*R*T_{2}}{V}

so total pressure is:

P_{total}=(n_{NO_{2}}+n_{NO})*\frac{R*T_{2}}{V}

replacing the moles we get:

P_{total}=(2*\frac{P_{1}V}{RT_{1}})*\frac{R*T_{2}}{V}

We know that T2=3*T1

replacing this value in the equation we get:

P_{total}=2*\frac{P_{1}V}{RT_{1}}*\frac{R*3T_{1}}{V}

P_{total}=6*P_{1} = 6*0.265 atm = 1.59 atm

5 0
4 years ago
Convert 0.63 mole of MG(OH)2 to mass in grams
Deffense [45]

Answer:

3.7939491450000004e+23

Explanation:

3 0
3 years ago
Read 2 more answers
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