Answer:
0.726 mol·L⁻¹
Step-by-step explanation:
c = moles/litres
=====
Moles = 29.8 × 1/342.30
Moles = 0.087 06 mol
=====
Litres = 120 × 1/1000
Litres = 0.120 L
=====
c = 0.087 06/0.120
c = 0.725 mol·L⁻¹
0.4411 I’m not sure but this is what I found
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Sorry I need to ask question
Number of millimoles of NaOH consumed in present titration =<span>33.23 X 0.09892
= 3.287
Thus, number of millimoles of vinegar present in sample = 3.287
Now, Molarity of vinegar solution = </span>
![\frac{\text{number of millimoles of vinegar}}{\text{volume of solution (ml)}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Ctext%7Bnumber%20of%20millimoles%20of%20vinegar%7D%7D%7B%5Ctext%7Bvolume%20of%20solution%20%28ml%29%7D%7D%20)
<span> = </span>
![\frac{3.287}{26.89}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3.287%7D%7B26.89%7D%20)
<span> = 0.1222 mol/dm3
Molar concentration of vinegar present in sample solution is 0.1222 M </span>