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Bess [88]
4 years ago
12

If Spongebob is under water than what is the substance beneath the water that they swim in

Chemistry
2 answers:
Mariana [72]4 years ago
8 0

Answer:

The seafloor

Explanation:

the bottom of the ocean, aka the sea floor.

usually made from sand

-Dominant- [34]4 years ago
4 0

Answer:

H2O

Explanation:

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Identify and label the Brønsted-Lowry acid, its conjugate base, the Brønsted-Lowry base, and its conjugate acid in each of the f
julia-pushkina [17]

Explanation:

As per Brønsted-Lowry concept of acids and bases, chemical species which donate proton are called Brønsted-Lowry acids.

The chemical species which accept proton are called Brønsted-Lowry base.

(a) HNO_3 + H_2O \rightarrow H_3O^+ + NO_3^-

HNO_3 is Bronsted lowry acid and NO_3^- is its conjugate base.

H_2O is Bronsted lowry base and H_3O^+ is its conjugate acid.

(b)

CN^- + H_2O \rightarrow HCN + OH^-

CN^- is Bronsted lowry base and HCN is its conjugate acid.

H_2O is Bronsted lowry acid and OH^- is its conjugate base.

(c)

H_2SO_4 + Cl^- \rightarrow HCl + HSO_4^-

H_2SO_4 is Bronsted lowry acid and HSO_4^- is its conjugate base.

Cl^- is Bronsted lowry base and HCl is its conjugate acid.

(d)

HSO_4^-+OH^- \rightarrow SO_4^{2-}+H_2O

HSO_4^- is Bronsted lowry acid and SO_4^{2-} is its conjugate base.

OH^- is Bronsted lowry base and H_2O is its conjugate acid.

(e)

O_{2-}+H_2O \rightarrow 2OH^-

O_{2-} is Bronsted lowry base and OH- is its conjugate acid.

H_2O is Bronsted lowry acid and OH- is its conjugate base.

6 0
3 years ago
Why do some elements that are classified as metals not look metallic?
Shkiper50 [21]

Answer:

So, that students like us get confuse!!!

Explanation:

6 0
3 years ago
If a gas has a volume of 750 mL at 25oC, what would the volume of the gas be at 55oC?
blagie [28]

Answer:

The answer to your question is     V2 = 825.5 ml

Explanation:

Data

Volume 1 = 750 ml

Temperature 1 = 25°C

Volume 2= ?

Temperature 2 = 55°C

Process

Use the Charles' law to solve this problem

                V1/T1 = V2/T2

-Solve for V2

                V2 = V1T2 / T1

-Convert temperature to °K

T1 = 25 + 273 = 298°K

T2 = 55 + 273 = 328°K

-Substitution

                V2 = (750 x 328) / 298

-Simplification

                V2 = 246000 / 298

-Result

                V2 = 825.5 ml

             

7 0
3 years ago
13. Which are the simplest pure substances that cannot be broken down into any other substances?​
Dima020 [189]

Answer:

Elements

Explanation:

Each kind of atom is an element. Elements are pure substances that cannot be broken down into simpler substances by ordinary chemical means.

4 0
3 years ago
Read 2 more answers
Identify the species that is oxidized and the species that is reduced in this reaction. Also, identify the oxidizing agent and t
natulia [17]

Answer:

Given the equation of the reaction below:

3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)

The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.

Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.

Note: the question is incomplete. a related question is given as follows; Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfer reaction. 3Cl2 + 2Al → 6Cl - + 2Al3+ species oxidized:

Explanation:

An oxidation is a process in which there is a loss of electrons whereas  reduction is a process involving the gain of electrons. A redox reaction is a reaction in which oxidation and reduction processes occur concurrently and to the same extent.

In a redox reaction reaction, the substance which is oxidized serves as the reducing agent by donating electrons to the substance which is reduced. On the other hand, the substance which is reduced serves as the oxidizing agent by accepting the electrons donated by the substance which is oxidized. In oxidation, the oxidation number of the substance oxidized increases, whereas in reduction, the oxidation number of the substance decreases.

For example, given the equation of the reaction below:

3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)

The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.

Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.

6 0
3 years ago
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