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3 years ago

I need help with problems 25 and 26.

Mathematics

2 answers:

Pani-rosa [81]3 years ago

4 0

25) Amount of 1 time weeding the garden = $8
   So, when Alfred weeded it 6 times, the equation would be:
   8x = 8*6 = $48
   So, He earned $48 in that.

26) Here, According to question,
   m/3 = 6
   m = 6*3 = 18
   So, she ran 18 miles in a month.
   You can check it by dividing number of miles in one week, as follows:
   18/6 = 3 (which is relation to it's month running distance)

Hope this helps! PM me in case of doubt!!

sineoko [7]3 years ago

3 0

25.48÷8=6
26.6-1+1-3in that's your choice or answer

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vladimir1956 [14]

Distribute the negative outside the parenthesis through the terms inside the parenthesis.

-c + 3 = 6

Subtract 3 from both sides.

-c = 3

Divide both sides by -1.

c = -3

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Solve 5x + 14 = k for x.

Y_Kistochka [10]

Answer:

x = (k-14)/5

Step-by-step explanation:

5x + 14 = k

Subtract 14 from each side

5x + 14-14 = k-14

5x = k-14

Divide by 5

5x/5 = (k-14)/5

x = (k-14)/5

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3 years ago

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AaBbCc x AaBbCc (use for all 3 questions) 1. What is the probability that this individual will: AABBcc 2. What is the probabilit

tankabanditka [31]

Answer: 1. P = 1/64

2. P = 1/32

3. P = 1/8

Step-by-step explanation:

In genetics, an ofspring inherits one copy of an allele of each parent, which can be described in the tables below called Punnett Square:

For crossing Aa x Aa:

A a

A AA Aa

a Aa aa

For crossing Bb x Bb:

B b

B BB Bb

b Bb bb

For crossing Cc x Cc:

C c

C CC Cc

c Cc cc

We can separate them because they are assorted independently.

For offspring with genotype AABBcc, probability will be:

P(AA) = 1/4

P(BB) = 1/4

P(cc) = 1/4

As all three probabilities has to happen at the same time, it is a "E" rule:

P(AABBcc) = $(\frac{1}{4}) (\frac{1}{4}) (\frac{1}{4})$

P(AABBcc) = 1/64

Probability for the individual to be AABBcc is 1/64 or 1.56%.

Genotype AaBBcc:

P(Aa) = 2/4 = 1/2

P(BB) = 1/4

P(cc) = 1/4

P(AaBBcc) = $(\frac{1}{2}) (\frac{1}{4}) (\frac{1}{4})$

P(AaBBcc) = 1/32

Probability for the individual to be AaBBcc is 1/32 or 3.12%

Genotype AaBbCc:

P(Aa) = 1/2

P(Bb) = 1/2

P(Cc) = 1/2

P(AaBbCc) = $(\frac{1}{2}) (\frac{1}{2}) (\frac{1}{2})$

P(AaBbCc) = 1/8

Probability for the individual to be AaBbCc is 1/8 or 12.5%.

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3 years ago

Does anyone know the correct answer ?? Will mark brainliest

leonid [27]

Answer:

c. 10.8

Step-by-step explanation:

this is bad but i did that work and i kept getting 10.6 and 10.8 is the closest so...

cos (45) = x/15 *put cos (45) over 1 & cross multiply*

x = 15 (cos (45))

x = 10.6

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3 years ago

A Clothing shop sold 140 Jackets an d 60 rain coats during the winter sale . Find the ratio of the number of raincoats sold to t

inessss [21]

Answer:

3:7

Step-by-step explanation:

60 ratio 140

Divide both sides by 10

6 ratio 14

Divide both sides by 2

3 ratio 7

3:7 ✔️

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2 years ago