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Sedaia [141]
3 years ago
13

*Line segment AB is divided into 4 unequal parts by points C, D, and E (in this order). The distance between midpoints of segmen

ts AC and EB is 30 cm. Find the distance between the midpoints of segments CD and DE , if AB = 36 cm.
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Let X and Y represent the midpoints of AC and EB, respectively. We are given

AB = 36

XY = 30

We know that AX +XY +YB = AB = 36, so AX+YB = 36-30 = 6. We also know that AX = XC and EY = YB, so XC+EY = AX+YB = 6.

Since XC +CE + EY = XY = 30, and XC+EY = 6, we must have CE = 30-6 = 24.

The distance between the midpoints of CD and DE will be half the length of CE, so will be 12 cm.

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zubka84 [21]

Answer:

27

Step-by-step explanation:

15.75/0.60=26.25

if we round it up, Erin needs to sell 27 cookies

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find a set of parametric equations of the line the line pases through the point (2,3,4) and is parallel to the xz-plane and the
joja [24]

Answer:

x=2, y=3, z=4+t

Step-by-step explanation:

For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:

u= (u_x, u_y, u_z)= (0,0,1)

Or any factor of u but for simplicity let's take the unitary vector.

Then the parametric equations are given by:

x= P_x + u_x t

y= P_y + u_y t

z= P_z + u_z t

Where the point given P=(2,3,4)= (P_x , P_y, P_z)

And then since we have everything we can replace like this:

x= P_x + u_x t 2+ 0*t = 2

y= P_y + u_y t= 3+ 0*t = 3

z= P_z + u_z t = 4+ 1t = 4+t

x=2, y=3, z=4+t

6 0
3 years ago
The planet venus is on average 2.5x10^7 kilometers from earth. The planet mars is on average 2.25x10^8 kilometers from earth. Wh
umka21 [38]

Answer:

The average distance from venus to mars is 2.5x10⁸ kilometers.

Step-by-step explanation:

We know:

d₁: average distance between venus and earth = 2.5x10⁷ km

d₂: average distance between mars and earth = 2.25x10⁸ km

We can find the average distance from venus to mars as follows:

d_{t} = d_{1} + d_{2}

First, we need to equal the base power 10 so we can sum both distances:

2.25 \cdot 10^{8} = 2.25 \cdot 10^{7} \times 10 = 22.5 \cdot 10^{7} km      

Now, average distance:

d_{t} = 2.5 \cdot 10^{7} + 22.5 \cdot 10^{7} = (2.5 + 22.5) \cdot 10^{7} = 25 \cdot 10^{7} km = 2.5 \cdot 10^{8} km

Therefore, the average distance from venus to mars is 2.5x10⁸ kilometers.

I hope it helps you!              

6 0
3 years ago
What is the greatest common factor of 16, 20, and 6?
KatRina [158]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
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