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3 years ago

Solve the following by factoring. 12x^2 -7x -12 = 0

Mathematics

1 answer:

nirvana33 [79]3 years ago

7 0

Solution:

The given equation is

$12x^2 -7x -12 = 0$

Now we will factor the middle term as per the ac-method because the given equation is a quadratic equation.

$12x^2 -7x -12 = 0\\\\12x^2-16x+9x-12=0\\\\4x(3x-4)+3(3x-4)=0\\\\(3x-4)(4x+3)=0\\\\3x-4=0,or, 4x+3=0\\\\x=\frac{4}{3},x=\frac{-3}{4}\\$

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Find the perimeter of a ruler that measures 6 inches by 5/6

alukav5142 [94]

Answer:

41/3

Step-by-step explanation:

6 + 6 + 5/6 + 5/6

3 0

3 years ago

Re-write the equation without the h component.

levacccp [35]

Answer:

$f(x) = 2[\frac{3^x}{9}] + 2$

$f(x) = 8(4)^x$

Step-by-step explanation:

Given

$f(x) = 2(3)^{x-2} + 2$

$f(x) = \frac{1}{2}(4)^{x+2}$

Required

Remove the h component

In a function, the h component is highlighted as:

$f(x) = a^{x+h}$

So, we have:

$f(x) = 2(3)^{x-2} + 2$

Split the exponents using the following law of indices:

$a^m/a^n = a^{m-n}$

$f(x) = 2*\frac{3^x}{3^2} + 2$

$f(x) = 2*\frac{3^x}{9} + 2$

$f(x) = 2[\frac{3^x}{9}] + 2$

<em>The h component has been removed</em>

$f(x) = \frac{1}{2}(4)^{x+2}$

Split the exponent using the following law of indices

$a^{m+n} =a^m * a^n$

So, we have:

$f(x) = \frac{1}{2}(4)^x * 4^2$

Express 4^2 as 16

$f(x) = \frac{1}{2}(4)^x * 16$

Divide 16 by 2

$f(x) = 8(4)^x$

3 0

2 years ago

A cable company charges a monthly fee for cable service plus an additional $3 for each premium channel. This is given by the fun

svlad2 [7]

Answer:

domain all real numbers

range all real numbers

the cost of his monthly cable is $40.50 when you plug in 4

3 0

2 years ago

The best recruitment source, that is, one which tends to result in attracting employees who experience greater loyalty, tenure,

Anna11 [10]

Answer:

The best recruitment source, that is, one which tends to result in attracting employees who experience greater loyalty, tenure, and job satisfaction than other recruiting sources,is **referrals from current employees**

Step-by-step explanation:

This is an HR question.

Referrals given to potential employees by current employees refer to the glowing references about the firm provided by those current employees to the potential employees.

The best set of people to talk about work conditions, pay, etc., at a workplace are the actual workers of that workplace.

Whenever they provide such privy information to a potential employee, it leaves no massive room for unpleasant surprises when the potential employee takes the job. The referrals basically groin the employee for the the best and the worst of such a workplace, that even qualified personnel, before taking up jobs, like to speak to current employees of that firm.

In HR, there's the popular saying that a firm is as good as the way they treat their employees.

So, such total information before taking a job leads to gaining employees that know all about what to expect and which realistic job satisfaction to target. Their realities after starting the job is often already calculated.

Hence, anyone that interacts with current employees of a firm and still takes up job with the firm, has a huge tendency to stay longer, be more loyal and have a bigger job satisfaction.

Hope this Helps!!!

6 0

3 years ago

Refer to the following scenario:You want to see if there is a difference between the exercise habits of Science majors and Math

bekas [8.4K]

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

$p_1=X_1/n_1=82/135=0.607$

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

$p_2=X_2/n_2=41/92=0.446$

The difference between proportions is (p1-p2)=0.162.

$p_d=p_1-p_2=0.607-0.446=0.162$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$\text{P-value}=2\cdot P(z>2.4014)=0.0171$

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

$MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.162-0.1735=-0.012\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.162+0.1735=0.335$

The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

6 0

3 years ago