Diameter of 6x and height of 2x+5 what is the volume of the cylinder
2 answers:
Answer:
(18x^3 + 45x^2)π unit^3.
Step-by-step explanation:
The radius of the base = 1/2 * 6x = 3x.
The volume = π r^2 h
= π * (3x)^2 * (2x + 5)
= 9x^2(2x + 5) π
= (18x^3 + 45x^2)π.
Answer:
V = pi*x^2*(18x - 45)
Step-by-step explanation:
If the diameter is 6x and the height is 2x + 5, we know that the radius is 3x.
Plugging this info into the volume-of-a-cylinder formula V = pi*r^2*h, we get:
V = pi*(3x)^2*(2x - 5), or V = pi*(9x^2)(2x -5), or:
V = pi*(18x^3 - 45x^2), or V = pi*x^2*(18x - 45)
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