Hi Help me with question 6b) pls
1 answer:
Answer:
k = 9
Step-by-step explanation:
Consider the pattern on the right side , that is
= k(k + 2) + 1 = k² + 2k + 1
Equating
k² + 2k + 1 = 100 ( subtract 100 from both sides )
k² + 2k - 99 = 0 ← in standard form
(k + 11)(k - 9) = 0 ← in factored form
Equate each factor to zero and solve for k
k + 11 = 0 ⇒ k = - 11
k - 9 = 0 ⇒ k = 9
But k > 0 , then k = 9
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Answer:
no
Step-by-step explanation:
The given lengths do not satisfy the Pythagorean theorem:
34² ≠ 33² +16²
1156 ≠ 1089 +256
The given sides do not form a right triangle.
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<em>Alternate solution</em>
You can also compute 34² -33² = (34+33)(34-33) = 67·1 = 67 ≠ 16².
Even simpler, a Pythagorean triple will never have zero or two even numbers. The numbers (16, 33, 34) cannot be a Pythagorean triple.
