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2 years ago

Hi Help me with question 6b) pls

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

5 0

Answer:

k = 9

Step-by-step explanation:

Consider the pattern on the right side , that is

$T_{k}$ = k(k + 2) + 1 = k² + 2k + 1

Equating

k² + 2k + 1 = 100 ( subtract 100 from both sides )

k² + 2k - 99 = 0 ← in standard form

(k + 11)(k - 9) = 0 ← in factored form

Equate each factor to zero and solve for k

k + 11 = 0 ⇒ k = - 11

k - 9 = 0 ⇒ k = 9

But k > 0 , then k = 9

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