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Radda [10]
3 years ago
7

What is 12a^-15ab-16a+20b in factored form ??

Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0
Since there are 4 terms you will "factor b y grouping"
3a(4 - 5b)  -4(4 - 5b)

each term has a common (4 - 5b) to factor out
(4 - 5b)(3a - 4)
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8m^3 - 28m^2 + 6m - 21. You solve by factoring by grouping!!! quick please
Leya [2.2K]

Answer:

(2m - 7)(4 {m}^{2}  + 3)

Step-by-step explanation:

8m^3 - 28m^2 + 6m - 21 \\  = 4 {m}^{2} (2 {m}  - 7) + 3(2m - 7) \\  = (2m - 7)(4 {m}^{2}  + 3)

4 0
3 years ago
Can someone help me with this? thanks
Sergio039 [100]

Answer:

least to greatest:

-11.7   -11.4   20/40  11.6

6 0
3 years ago
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Determine the most specific name for the figure in the diagram.
Makovka662 [10]
<span>ABCD is a parallelogram. Looking at the quadrilateral ABCD, the first thing to do is to determine if the opposite sides are parallel to each other. So let's check that by looking at the opposite sides. Line segment BA. When you go from point B to point A, you move to the right 1 space, and down 4 spaces. So the slope is -4. Looking at line segment CD, you also move to the right 1 space and down 4 spaces, which also means a slope of -4. So those two sides are parallel. When you compare line segments BC and AD, you'll notice that for both of them, you go to the right 5 spaces and up 2 spaces, so those too are parallel. So we can now saw that the quadrilateral ABCD is a parallelogram. Since ABCD is a parallelogram, we now need to check if it's a rectangle (we know it can't be a square since the sides aren't all the same length). An easy way to test if it's a rectangle is to check of one of the angles is 90 degrees. And if we draw a line from B to D, we can create a triangle ABD. And in a right triangle, due to Pythagora's theorem we know that A^2 + B^2 = C^2 where A is the line segment AB, B is the line segment AD and C is the line segment BD. So let's calculate A^2, B^2, and C^2. A^2: Line segment AB. We can construct a right triangle with A = 1 and B = 4. So C^2 = 1^2 + 4^2 = 1 + 16 = 17. So we have an A^2 value of 17 B^2: Line segment AD. We can construct a right triangle with A = 2 and B = 5. So C^2 = 2^2 + 5^2 = 4 + 25 = 29. So we have an B^2 value of 29 C^2: Line segment BD. We can construct a right triangle with A = 2 and B = 6. So C^2 = 2^2 + 6^2 = 4 + 36 = 40. So we have a C^2 value of 40. Now let's check if the equation A^2 + B^2 = C^2 is correct: 17 + 29 = 40 46 = 40 And since 46 isn't equal to 40, that means that ABCD can not be a rectangle. So it's just a parallelogram.</span>
6 0
3 years ago
A park is shaped like a trapezoid. It has an area of 7.2 square miles. One base is 1.2 miles, and the other base is 2.4 miles lo
WINSTONCH [101]
7.2÷(1.2+2.4)=2
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6 0
3 years ago
A horizontal line contains points A, C, B. 2 lines extend from point C. A line extends to point E and another line extends to po
Effectus [21]

Answer:

Option (2).

Step-by-step explanation:

In the figure attached,

A, C and B are the points lying on a straight line.

2 lines EC and DC have been drawn by extending the lines from C to E and D respectively.

Ray CE is the angle bisector of ∠ACD.

That means CE divides ∠ACD in two equal parts.

m∠ACE = m∠DCE

Since m∠ACD = m∠ACE + m∠DCE

                        = 2(m∠ACE)

          m∠ACE = \frac{1}{2}(\angle ACD)

Therefore, option (2) will be the answer.

6 0
3 years ago
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