Answer:
1. B
Step-by-step explanation:
Answer:
A. Answer is 2263.
Checkpoint 1 is -86 Checkpoint 4 is 2177
Subtract -86 from 2177....2177-(-86)
=2263
2263 is how much higher checkpoint 1 (-86) is from checkpoint 4 (2177)
B. 239 FEET.
the altitude of the hill must be subtracted by the depth of the ckeckpoint(2)(-189)
therefore the altitude of the hill comes out to be 428-189=239feet.
therefore,the actual altitude of the hill is 239 feet.
Step-by-step explanation:
Sn=n/2(2a+(n-1)d)
910=n/2{2a+(n-1)d}
1820=n{2a+(n-1)d}
1820=20{2a+(20-1)d}
1820=20{2a+19d}
91=2a+19d
An=a+(n-1)d
95=a+(20-1)d
95=a+19d
91=2a+19d
---------------
4=-a
a=-4
91=2a+19d
91=2(-4)+19d
91=-8+19d
91+8=19d
99=19d
d=99/19
A=-4
5.65 in decimal and 113/20
5280 feet in 1 mile
3600 seconds in an hour
58(5280) / 3600 = 306240/3600 = 85.06 ft per sec or if u need it rounded, it is 85.1
