To solve this we use the
equation,
<span> M1V1 = M2V2</span>
<span> where M1 is the
concentration of the stock solution, V1 is the volume of the stock solution, M2
is the concentration of the new solution and V2 is its volume.</span>
<span>
</span>
<span>M1 = .80 g H2SO4 / g solution (1018 g solution / L solution ) (1 mol / 98.08) = 8.30 M</span>
<span>
</span>
<span>8.30 (V1) = (5.0 M) (1.5 L)</span>
<span>V1 = 0.9036 L or 903.6 mL of the stock needed</span>
Answer:
x = (-19)/3
Step-by-step explanation:
Solve for x:
10 - 2 x + 5 (x + 4) + 3 (2 x + 9) = 0
5 (x + 4) = 5 x + 20:
10 - 2 x + 5 x + 20 + 3 (2 x + 9) = 0
3 (2 x + 9) = 6 x + 27:
6 x + 27 + 5 x - 2 x + 10 + 20 = 0
Grouping like terms, 6 x + 5 x - 2 x + 10 + 20 + 27 = (-2 x + 5 x + 6 x) + (10 + 20 + 27):
(-2 x + 5 x + 6 x) + (10 + 20 + 27) = 0
-2 x + 5 x + 6 x = 9 x:
9 x + (10 + 20 + 27) = 0
10 + 20 + 27 = 57:
9 x + 57 = 0
Subtract 57 from both sides:
9 x + (57 - 57) = -57
57 - 57 = 0:
9 x = -57
Divide both sides of 9 x = -57 by 9:
(9 x)/9 = (-57)/9
9/9 = 1:
x = (-57)/9
The gcd of 57 and 9 is 3, so (-57)/9 = (-(3×19))/(3×3) = 3/3×(-19)/3 = (-19)/3:
Answer: x = (-19)/3
3 * 5/12 = 15/12 = 1 1/4 hrs total
Answer:
12
Step-by-step explanation:
