Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
The location of point K as a mixed number is 8 6/8 = 8 3/4 because there are 8 lines, and point K is on the 6th line.
Hope this helped☺☺
Answer:
66.5 square feet
Step-by-step explanation:
We have to find the area of the doghouse which is in the shape of right trapezoid . that is, Substitute the values, we get, Hence, Area of of the doghouse which is in the shape of right trapezoid is 66.5 square feet.
Answer:
H
Step-by-step explanation:
there is 10 parts to the shape so your denominator would be 10 then if you count the shaded area there's 8, so 8 would be your numerator
8/10 = 0.8 or 80%
