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3 years ago

Halfway through her run when the music stopped playing, was there energy in Mila’s phone? Why or why not?

Physics

1 answer:

denpristay [2]3 years ago

6 0

Yea. Sound energy. It was most likely I am pretty sure. If she was listening to it................hope this is right

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the initial kinetic energy of an object moving on a horizontal surface is K. Friction between the object and the surface causes

Ugo [173]

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3 years ago

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help! im timed. A ball is thrown downward with an initial velocity of 12.1 m/s. How long will it take to reach a velocity of -24

Ulleksa [173]

Answer:

$1.27\:\text{s}$

Explanation:

We can use the following kinematics equation to solve this problem:

$v_f=v_i+at$

Solving for $t$ :

$-24.5=-12.1+-9.8t,\\-12.4=-9.8t,\\t=\frac{-12.4}{-9.8}\approx \boxed{1.27\:\mathrm{s}}$

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3 years ago

Help me please with this homework

liq [111]

Because each case i observed happened due to the experiments that I did with my partner.

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3 years ago

Prove that..<br>please help<br>

GaryK [48]

$\large{ \boxed{ \bf{ \color{red}{Universal \: law \: of \: gravitation}}}}$

Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of the distance between them. The forces along the line joining the centre of the two objects.

❍ Let us consider two masses m1 and m2 line at a separation distance d. Let the force of attraction between the two objects be F.

According to universal law of gravitation,

$\large{ \longrightarrow{ \rm{F \propto m_1 m_2}}}$

Also,

$\large{ \longrightarrow{ \rm{ F \propto \dfrac{1}{ {d}^{2} } }}}$

Combining both, We will get

$\large{ \longrightarrow{ \rm{F \propto \dfrac{ m_1 m_2}{ {d}^{2}}}}}$

Or, We can write it as,

$\large{ \longrightarrow{ \rm{F \propto \: G \dfrac{ m_1 m_2}{ {d}^{2} }}}}$

Where, G is the constant of proportionality and it is called 'Universal Gravitational constant'.

☯️ Hence, derived !!

<u>━━━━━━━━━━━━━━━━━━━━</u>

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3 years ago

What is/are the external cause code(s) for a passenger involved in a mva that lost control on the highway and hits a guardrail?

Sholpan [36]

Here is the answer. The external cause code for a passenger that is involved in a MVA that lost control on the highway and hits a guardrail is E815. Your fifth digit is a 1 for a motor vehicle passenger. You would use an additional E code when a place of occurrence (example, home or parking lot) is documented. In this case, the location is documented as the highway. Hope this helps.

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4 years ago